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Question

我有两个长度不同但共享相似信息的对象数组。

qrySearchLocID = [{
    LocalLabID: '123f',
    SystemID: 5000152,
    AppLabID: 3
  },
  {
    LocalLabID: '12BC',
    SystemID: 5000384,
    AppLabID: 3
  },
];

和

qrySearch = [{
    sName: 'SomePlace1',
    lBusinessID: 37343,
    SystemID: 5000152
  },
  {
    sName: 'SomePlace2',
    lBusinessID: 39780,
    SystemID: 5000156
  },
  {
    sName: 'SomePlace3',
    lBusinessID: 50772,
    SystemID: 5000519
  },
  {
    sName: 'SomePlace4',
    lBusinessID: 31079,
    SystemID: 5000384
  },
]

我想基于SystemID组合这两个数组，从qrySearch复制所有信息并从qrySearchLocID添加LocalLabID而不是其他任何内容。例如，我希望结果数组为

[{
    sName: 'SomePlace1',
    lBusinessID: 37343,
    SystemID: 5000152,
    LocalLabID: '123f'
  },
  {
    sName: 'SomePlace2',
    lBusinessID: 39780,
    SystemID: 5000156
  },
  {
    sName: 'SomePlace3',
    lBusinessID: 50772,
    SystemID: 5000519
  },
  {
    sName: 'SomePlace4',
    lBusinessID: 31079,
    SystemID: 5000384,
    LocalLabID: '12BC'
  },
]

提前致谢。

Answer 1

您可以使用map和find功能。

＆＃13;

var qrySearchLocID = [{
    LocalLabID: '123f',
    SystemID: 5000152,
    AppLabID: 3
  },
  {
    LocalLabID: '12BC',
    SystemID: 5000384,
    AppLabID: 3
  },
];

var qrySearch = [{
    sName: 'SomePlace1',
    lBusinessID: 37343,
    SystemID: 5000152
  },
  {
    sName: 'SomePlace2',
    lBusinessID: 39780,
    SystemID: 5000156
  },
  {
    sName: 'SomePlace3',
    lBusinessID: 50772,
    SystemID: 5000519
  },
  {
    sName: 'SomePlace4',
    lBusinessID: 31079,
    SystemID: 5000384
  },
];

var result = qrySearch.map((e, _) => 
          (_ = qrySearchLocID.find((q) => q.SystemID === e.SystemID)) ? 
          { ...e, ...{ LocalLabID: _.LocalLabID } } : e);

console.log(result);

＆＃13;

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Answer 2

我的建议是将两者都转换为由SystemID键入的对象文字的中间形式。然后，您可以将所有属性添加到该对象，然后再转换回您需要的任何长期形式。

Answer 3

您可以使用Array.findIndex函数在符合特定条件的数组中查找索引，然后将信息添加到该索引处的对象：

＆＃13;

qrySearchLocID = [{
    LocalLabID: '123f',
    SystemID: 5000152,
    AppLabID: 3
  },
  {
    LocalLabID: '12BC',
    SystemID: 5000384,
    AppLabID: 3
  },
];
qrySearch = [{
    sName: 'SomePlace1',
    lBusinessID: 37343,
    SystemID: 5000152
  },
  {
    sName: 'SomePlace2',
    lBusinessID: 39780,
    SystemID: 5000156
  },
  {
    sName: 'SomePlace3',
    lBusinessID: 50772,
    SystemID: 5000519
  },
  {
    sName: 'SomePlace4',
    lBusinessID: 31079,
    SystemID: 5000384
  },
]

for(var i = 0; i < qrySearch.length; i++){
  var j = qrySearchLocID.findIndex(function(elem){
    return elem.SystemID == qrySearch[i].SystemID;
  });
  if(j != -1){
    qrySearch[i].LocalLabID = qrySearchLocID[j].LocalLabID;
  }
}

console.log(qrySearch)

＆＃13;

Answer 4

要加快查找速度，您可以先将第一个数组转换为由SystemID键入的Map。然后在第二个数组的map中使用它，在地图中查找SystemID并获取它的LocalLabID（如果存在）。

在这里，您可以看到一个功能表达式中发生的一切：

const qrySearchLocID = [ { LocalLabID: '123f', SystemID: 5000152, AppLabID: 3 },{ LocalLabID: '12BC', SystemID: 5000384, AppLabID: 3 }],
    qrySearch = [{ sName: 'SomePlace1', lBusinessID: 37343, SystemID: 5000152},{ sName: 'SomePlace2', lBusinessID: 39780, SystemID: 5000156 },{ sName: 'SomePlace3', lBusinessID: 50772, SystemID: 5000519 },{ sName: 'SomePlace4', lBusinessID: 31079, SystemID: 5000384 }];
    
const result = qrySearch.map(
    (map => o => Object.assign(o, map.has(o.SystemID) 
                                  && { LocalLabID: map.get(o.SystemID) }))
        (new Map(qrySearchLocID.map(loc => [loc.SystemID, loc.LocalLabID])))
);

console.log(result);

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如何根据Javascript中的属性组合两个不同大小的对象数组？

4 个答案:

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