I've have to log changes of each entities. I've Listener which listen for doctrine's events on preRemove, postUpdate and postDelete. My enity AccessModule has relations:
App\Entity\AccessModule.php
/**
* @ORM\OneToMany(targetEntity="App\Entity\AccessModule", mappedBy="parent")
* @ORM\OrderBy({"id" = "ASC"})
*/
private $children;
/**
* @ORM\ManyToOne(targetEntity="App\Entity\AccessModule", inversedBy="children")
* @ORM\JoinColumn(name="parent_id", referencedColumnName="id", nullable=true)
*/
private $parent;
/**
* @ORM\ManyToMany(targetEntity="App\Entity\AccessModuleRoute", inversedBy="access_modules")
* @ORM\JoinTable(name="access_routes",
* joinColumns={@ORM\JoinColumn(name="access_module_id", referencedColumnName="id")},
* inverseJoinColumns={@ORM\JoinColumn(name="route_id", referencedColumnName="id")})
*
*/
private $routes;
in listener: App\EventListener\EntityListener.php
use Symfony\Component\Serializer\Encoder\JsonEncoder;
use Symfony\Component\Serializer\Encoder\XmlEncoder;
use Symfony\Component\Serializer\Normalizer\ObjectNormalizer;
$encoders = [new XmlEncoder(), new JsonEncoder()];
$normalizer = new ObjectNormalizer();
$normalizer->setCircularReferenceHandler(function ($object) {
return $object->getId();
});
$this->serializer = new Serializer([$normalizer], $encoders);
public function createLog(LifecycleEventArgs $args, $action){
$em = $args->getEntityManager();
$entity = $args->getEntity();
if ($this->tokenStorage->getToken()->getUser()) {
$username = $this->tokenStorage->getToken()->getUser()->getUsername();
} else {
$username = 'anon'; // TODO Remove anon. set null value
}
$log = new Log();
// $log->setData('dddd')
$log->setData($this->serializer->serialize($entity, ''json)
->setAction($action)
->setActionTime(new \DateTime())
->setUser($username)
->setEntityClass(get_class($entity));
$em->persist($log);
$em->flush();
}
I've problem with serialization
When I use $log->setData($entity) I get problem with Circular.
Whan I do serialization $log->setData($this->serializer->serialize($entity, ''json) I get full of relations, with parent's children, with children children. In a result I get full tree :/
I'd like to get
Expect
[
'id' => ID,
'name' => NAME,
'parent' => parent_id // ManyToOne, I'd like get its id
'children' => [$child_id, $child_id, $child_id] // array of $id of children array collection
]
(ofcourse this is draft before encode it to json)
How can I get expected data without full relations?
答案 0 :(得分：2)
现在让我解释它是如何工作的。这很简单。假设你有帖子实体：
class Post
{
/**
* @ORM\Id
* @ORM\GeneratedValue
* @ORM\Column(type="integer")
* @Groups({"default"})
*/
private $id;
/**
* @ORM\ManyToOne(targetEntity="App\Entity\User\User")
* @Groups({"default"})
*/
private $author;
}
你还有用户实体：
class User
{
/**
* @ORM\Id
* @ORM\GeneratedValue
* @ORM\Column(type="integer")
* @Groups({"default"})
*/
private $id;
/**
* @ORM\Column(type="string", length=40)
* @Groups({"default"})
*/
private $firstName;
/**
* @ORM\Column(type="string", length=40)
*/
private $lastName;
}
帖子可以有作者（用户），但我不想每次都返回所有用户数据。我只对id和名字感兴趣。
仔细查看 @Groups 注释。您可以指定所谓的序列化组。它只是告诉Symfony您希望在结果集中包含哪些数据的便捷方式。
您必须通过在属性/ getter上方添加注释形式的相关组来告诉Symfony序列化程序您希望保留哪些关系。您还必须指定要保留的关系的属性或getter。
现在如何让Symfony知道这些东西？
准备/配置序列化服务时，您只需提供如下定义的组：
return $this->serializer->serialize($data, 'json', ['groups' => ['default']]);
围绕本机symfony序列化程序构建某种包装器服务是很好的，这样可以简化整个过程并使其更具可重用性。
还要确保序列化程序配置正确 - 否则不会考虑这些组。
这也是“处理”循环引用的一种方式（以及其他方式）。
现在您只需要研究如何格式化结果集。
答案 1 :(得分：2)
在Symfony 4.1中进行了测试，这是实际上有效的文档https://symfony.com/blog/new-in-symfony-2-7-serialization-groups
Robert的解释https://stackoverflow.com/a/48756847/579646缺少$ classMetadataFactory才能正常工作。这是我的代码：
$classMetadataFactory = new ClassMetadataFactory(new AnnotationLoader(new AnnotationReader()));
$encoders = [new JsonEncoder()];
$normalizer = new ObjectNormalizer($classMetadataFactory);
$normalizer->setCircularReferenceLimit(2);
// Add Circular reference handler
$normalizer->setCircularReferenceHandler(function ($object) {
return $object->getId();
});
$normalizers = [$normalizer];
$serializer = new Serializer($normalizers, $encoders);
$jsonContent = $serializer->serialize($jobs, 'json', array('groups' => ['default']));
return JsonResponse::fromJsonString($jsonContent);
答案 2 :(得分：2)
我同意max4ever关于Roberts的回答。不对我已经测试过max4ever的解决方案，并且在Symfony 4.2上运行良好。
但是，我想向表中添加一个更简单的解决方案。您可以使用$normalizer->setignoredattributes()完全完全忽略属性。无需对属性，工厂，注释进行分组。很简单的。看看。
use Symfony\Component\Serializer\Serializer;
use Symfony\Component\Serializer\Encoder\JsonEncoder;
use Symfony\Component\Serializer\Normalizer\ObjectNormalizer;
$normalizer = new ObjectNormalizer();
$normalizer->setIgnoredAttributes(array('age'));
$encoder = new JsonEncoder();
$serializer = new Serializer(array($normalizer), array($encoder));
$serializer->serialize($person, 'json');
关键是：
$normalizer->setIgnoredAttributes(array('age'));
那只是文档中的示例，您可以在此处阅读： https://symfony.com/doc/current/components/serializer.html#ignoring-attributes
我想添加我的使用方案，以防偶然帮助某人。因此，我试图在Symfony项目上将Axios与VueJs一起使用，因此我需要将一些json发送到前端。不幸的是，我尝试序列化的对象与Users对象具有ManyToOne关系。因此，在这里，我调试了“ 序列化类的对象时检测到循环引用... ”。我只是将这段代码放在控制器中。
use Symfony\Component\Serializer\Serializer;
use Symfony\Component\Serializer\Encoder\JsonEncoder;
use Symfony\Component\Serializer\Normalizer\ObjectNormalizer;
$user = $this->getUser(); // get the current user.
$lists = $this->getDoctrine()->getRepository(Lists::class)->findBy(array('userid' => $user->getId())); // Find all lists owned by current user.
$normalizer = new ObjectNormalizer();
$normalizer->setIgnoredAttributes(array('userid')); // I only want data about each list. $userid is a reference back to the user that owns the list. So we ignore userid.
$encoder = new JsonEncoder();
$serializer = new Serializer(array($normalizer), array($encoder));
$json = $serializer->serialize($lists, 'json');
return JsonResponse::fromJsonString($json);
截至2018年12月17日使用Symfony 4.2的作品。