Question

我需要使用日期格式和系统日期中的列Dob将出生日期转换为当前年龄，但是将结果填充到dob列中。日期格式为dd-mm-yy。我已经尝试使用to_char和to_number函数从sys日期中减去

Answer 1

假设您只需要多年且dob列为date，您可能需要：

select dob, floor(months_between(sysdate, dob) / 12) age
from yourTable

例如：

with yourTable(dob) as (
    select date '2000-02-01' from dual union all
    select date '2000-02-02' from dual union all
    select date '2000-01-31' from dual 
    )
select dob, floor(months_between(sysdate, dob) / 12) age
from yourTable

给出：

DOB               AGE
---------- ----------
2000-02-01         18
2000-02-02         17
2000-01-31         18

3 rows selected.

Answer 2

如果您需要date_of_birth列的年，月和日。你可以这样做。

select sysdate,
  date_of_birth,
  trunc(months_between(sysdate,date_of_birth) / 12) as years,
  trunc(months_between(sysdate,date_of_birth) -
    (trunc(months_between(sysdate,date_of_birth) / 12) * 12)) as months,
  trunc(sysdate) - add_months(date_of_birth, trunc(months_between(sysdate,date_of_birth))) as days
from table_name;

Oracle将出生日期改为年龄

2 个答案: