Question

我的JSON数据有什么问题？

var myJSON = [
  {"x":108,  "y":58, "w":431, "h":23},
  {"x":203, "y":121,  "w":240, "h":47},
  {"x":64, "y":183, "w":138, "h":9},
  {"x":140,  "y":208, "w":85, "h":7},
  {"x":51,  "y":225,  "w":263,  "h":135},
  {"x":51,  "y":376,  "w":75, "h":7},
  {"x":51,  "y":393, "w":263, "h":123},
  {"x":51, "y":532,  "w":263,  "h":112},
  {"x":51, "y":655,  "w":263,  "h":112},
  {"x":334, "y":183,  "w":68,  "h":9},
  {"x":333, "y":508,  "w":262,  "h":112},
  {"x":417, "y":645,  "w":95,  "h":7},
  {"x":332, "y":664,  "w":264,  "h":103},
  {"x":441, "y":488,  "w":47,  "h":7},
  {"x":333, "y":508,  "w":262,  "h":112}
];

当我尝试解析var myObj = JSON.parse(myJSON);时，我收到以下错误：

SyntaxError：JSON.parse：第1行第2列的意外字符   JSON数据
  [了解更多]

Answer 1

JSON.parse()需要一个JSON字符串并将其解析/转换为一个对象。
JSON.stringify()期望对象并将其字符串化/转换为JSON字符串。

您正在尝试使用JSON.parse()来解析对象，这没有任何意义。

由于您的数据已经是一个对象（an array is an object），您可以立即将其分配给myObj，跳过解析步骤：

var myObj = [
  {"x":108,  "y":58, "w":431, "h":23},
  {"x":203, "y":121,  "w":240, "h":47},
  {"x":64, "y":183, "w":138, "h":9},
  {"x":140,  "y":208, "w":85, "h":7},
  {"x":51,  "y":225,  "w":263,  "h":135},
  {"x":51,  "y":376,  "w":75, "h":7},
  {"x":51,  "y":393, "w":263, "h":123},
  {"x":51, "y":532,  "w":263,  "h":112},
  {"x":51, "y":655,  "w":263,  "h":112},
  {"x":334, "y":183,  "w":68,  "h":9},
  {"x":333, "y":508,  "w":262,  "h":112},
  {"x":417, "y":645,  "w":95,  "h":7},
  {"x":332, "y":664,  "w":264,  "h":103},
  {"x":441, "y":488,  "w":47,  "h":7},
  {"x":333, "y":508,  "w":262,  "h":112}
];

Answer 2

仅当您要将JSON.parse解析为javascript对象时，

string才有效。如果你已经有一个javasript对象（或数组），你不需要JSON.parse：

＆＃13;

var myJSON = `[
  {"x":108,  "y":58, "w":431, "h":23},
  {"x":203, "y":121,  "w":240, "h":47},
  {"x":64, "y":183, "w":138, "h":9},
  {"x":140,  "y":208, "w":85, "h":7},
  {"x":51,  "y":225,  "w":263,  "h":135},
  {"x":51,  "y":376,  "w":75, "h":7},
  {"x":51,  "y":393, "w":263, "h":123},
  {"x":51, "y":532,  "w":263,  "h":112},
  {"x":51, "y":655,  "w":263,  "h":112},
  {"x":334, "y":183,  "w":68,  "h":9},
  {"x":333, "y":508,  "w":262,  "h":112},
  {"x":417, "y":645,  "w":95,  "h":7},
  {"x":332, "y":664,  "w":264,  "h":103},
  {"x":441, "y":488,  "w":47,  "h":7},
  {"x":333, "y":508,  "w":262,  "h":112}
  ]`; 

console.log(JSON.parse(myJSON));

＆＃13;

Answer 3

您正在尝试将JSON对象解析为JSON对象，如果您的myJSON已经是对象，则不需要这样做。

如果将其存储为字符串，那么JSON.parse()将非常有用。

Answer 4

为什么要解析JSON对象？您确定不想将其转换为字符串格式（使用JSON.stringify（））???

Answer 5

JSON.parse()方法解析JSON字符串，构造字符串描述的JavaScript值或对象。可以提供可选的reviver函数，以在返回结果对象之前对其执行转换。

 var json = '{"result":true, "count":42}';
    obj = JSON.parse(json);

    console.log(obj.count);
    // expected output: 42

    console.log(obj.result);
    // expected output: true

我的JSON数组格式有什么问题？

5 个答案: