Question

我有以下XML结构（文件＃1），我需要编写XSL文件，以便将其转换为不同的结构（文件＃2）。目的：需要导入到DB。

在文件＃1中可能有多个对象。文件＃1中的每个对象将基于XML文件＃2转换到我的表中的4条记录。

你能帮我解决XSL语法吗？

感谢您的帮助。

文件＃1：

<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
<Root>
    <Object>
        <location>[X12][Y20]</location>
        <serial>1224719</serial>
        <side_left>
            <color>black</color>
            <point>
                <name>1</name>
                <value>2</value>
            </point>
            <point>
                <name>2</name>
                <value>3</value>
            </point>
            <total>5</total>
        </side_left>
        <side_right>
            <color>yellow</color>
            <point>
                <name>1</name>
                <value>5</value>
            </point>
            <point>
                <name>2</name>
                <value>6</value>
            </point>
            <total>11</total>
        </side_right>
    </Object>
</Root>

档案＃2

<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
    <Root>
        <MyTable>
            <serial>1224719</serial>
            <location>[X12][Y20]</location>
            <color>black</color>
            <name>1</name>
            <value>2</value>
        </MyTable>
        <MyTable>
            <serial>1224719</serial>
            <location>[X12][Y20]</location>
            <color>black</color>
            <name>2</name>
            <value>3</value>
        </MyTable>
        <MyTable>
            <serial>1224719</serial>
            <location>[X12][Y20]</location>
            <color>yellow</color>
            <name>1</name>
            <value>5</value>
        </MyTable>
        <MyTable>
            <serial>1224719</serial>
            <location>[X12][Y20]</location>
            <color>yellow</color>
            <name>2</name>
            <value>6</value>
        </MyTable>
    </Root>

Answer 1

试试这个：

 <xsl:template match="Root">
    <xsl:copy>
        <xsl:for-each select="//point">
            <MyTable>
                <xsl:copy-of select="ancestor::Object/serial"/>
                <xsl:copy-of select="ancestor::Object/location"/>
                <xsl:copy-of select="../color"/>
                <xsl:copy-of select="*"/>
            </MyTable>
        </xsl:for-each>
    </xsl:copy>
</xsl:template>

请参阅http://xsltransform.net/aiwQ3u

处的转化

对于您的其他查询，请尝试此

    <xsl:template match="Root">
    <xsl:copy>
        <xsl:for-each select="//point">
            <MyTable>
                <xsl:copy-of select="ancestor::Object/serial"/>
                <locationX><xsl:value-of select="substring-before(substring-after(ancestor::Object/location, 'X'), ']')"/></locationX>
                <locationY><xsl:value-of select="substring-before(substring-after(ancestor::Object/location, 'Y'), ']')"/></locationY>
                <xsl:copy-of select="../color"/>
                <xsl:copy-of select="*"/>
            </MyTable>
        </xsl:for-each>
    </xsl:copy>
</xsl:template>

为Xml创建XSL到表转换

1 个答案: