Question

我控制器中的代码

public function see($users_parent_id)
{
  $data['data'] = Downline::where('users_parent_id',$users_parent_id)->first();
  $data['data2'] = Downline::where('users_parent_id',$users_parent_id)->get();
  $data['data3'] = Downline::where('users_parent_id',$data['data']->users_id)->get();
  $data['users'] = User::where('role','member')->get();

  return view('backend.pages.downline.show', $data);
}

和我在jstree中的循环数据

<script>
$(function() {
  var arrayCollection = [
    {"id": "{{ $data->users_parent_id }}", "parent": "#", "text": "{{ $data->users_parent->fullname }}"},
    @foreach($data2 as $item2)
      {"id": "{{ $item2->users_id }}", "parent": "{{ $data->users_parent_id }}", "text": "{{ $item2->users->fullname }}"},
    @endforeach
    @foreach($data3 as $item3)
      {"id": "{{ $item3->users_id }}", "parent": "{{ $item3->users_parent_id }}", "text": "{{ $item3->users->fullname }}"},
    @endforeach
  ];

  $('#container').jstree({
    'core': {
      'data': arrayCollection
    }
  });
});

我的问题：如何在不使用大量foreach的情况下在jstree中循环laravel数据？

Answer 1

您可以使用if let cgcontext = UIGraphicsGetCurrentContext() { cgcontext.strokeEllipse(in: CGRect(x: center.x-diameter/2, y: center.y-diameter/2, width: diameter, height: diameter)) }创建关联数组，然后使用laravel辅助函数array_map将其传递给视图。

如何在jstree中循环数据laravel

1 个答案: