无法识别a的嵌套查询。
SELECT
a.Emp_No,
SUM(b.[Reg_Hours]) AS [Clocked Regular Hours],
SUM(a.[Regular_Hours]) AS [Paid Regular Hours],
SUM(b.[OT_Hrs]) AS [Clocked OT Hours],
SUM(a.[Overtime_Hours]) AS [Paid Overtime Hours]
FROM (SELECT
Lenrold_Payroll_Transactions.Employee_No AS Emp_No,
SUM(Regular_Hours) AS [Paid Regular Hours],
SUM(Overtime_Hours) AS [Paid Overtime Hours]
FROM Lenrold_Payroll_Transactions
GROUP BY Lenrold_Payroll_Transactions.Employee_No) AS a,
Lenrold_Payroll_Time AS b
WHERE a.Employee_No = b.Emp_No;
答案 0 :(得分:0)
我的猜测是你的SQL引擎不喜欢你正在使用的隐式连接语法。使用显式连接重写查询:
SELECT
a.Emp_No,
b.[Clocked Regular Hours],
a.[Paid Regular Hours],
b.[Clocked OT Hours],
a.[Paid Overtime Hours]
FROM
(
SELECT
Employee_No,
SUM(Regular_Hours) AS [Paid Regular Hours],
SUM(Overtime_Hours) AS [Paid Overtime Hours]
FROM Lenrold_Payroll_Transactions
GROUP BY Employee_No
) AS a
INNER JOIN
(
SELECT
Emp_No,
SUM(Reg_Hours) AS [Clocked Regular Hours],
SUM(OT_Hrs) AS [Clocked OT Hours]
FROM Lenrold_Payroll_Time
GROUP BY Emp_No
) AS b
ON a.Employee_No = b.Emp_No;