当Form中有多个时,Angular FormControls始终有效

时间:2018-01-31 23:56:36

标签: angular angular-forms angular-validation

我有两个使用FormControl的输入始终显示为有效,但是如果我取出一个输出则剩余的将按预期有效/无效。我会为一个ControlGroup更改两个formcontrols但是1.)我想了解我做错了什么以及2.)我需要访问一个formcontrol以获得我在组件中的自动完成功能。

任何指出我错的地方都会受到赞赏,提前谢谢!

相关HTML:

<form 
    fxLayout="column" 
    fxLayoutAlign="center center" 
    (ngSubmit)="onSubmit(status, count)" 
    #statusForm="ngForm"
>

    <!-- Status Input -->
    <div>
        <mat-form-field>
        <input 
            matInput placeholder="Status" 
            [formControl]="statusFormControl"
            [errorStateMatcher]="matcher"
            [matAutocomplete]="auto"
            [(ngModel)]="status"
            name="status"
            required
        >
        <mat-error *ngIf="statusFormControl.hasError('required')">
            Status is <strong>required</strong>
        </mat-error>
    </mat-form-field>

    <mat-autocomplete #auto="matAutocomplete">
        <mat-option *ngFor="let status of filteredStatusList | async" [value]="status.name">
        {{ status.name }}
        </mat-option>
    </mat-autocomplete>
    </div>


    <!-- Count Input -->
    <mat-form-field>
        <input 
            matInput placeholder="Count" 
            [formControl]="countFormControl"
            type="number"
            min="1"
            [(ngModel)]="count"
            name="count"
            required
        >
        <mat-error *ngIf="countFormControl.hasError('required')">
            Count must be a <strong>number</strong>
        </mat-error>
    </mat-form-field>

    {{statusForm.valid}}
    {{statusForm.invalid}}

    <button 
        mat-raised-button color="primary" 
        *ngIf="statusForm.valid" 
        type="submit" 
        [disabled]="statusForm.invalid"
    >
        Add
    </button>

和TS:

export class ... {

statusFormControl = new FormControl('', [
    Validators.required
]);

countFormControl = new FormControl('', [
    Validators.required
]);

...

constructor() {
this.filteredStatusList = this.statusFormControl.valueChanges
  .pipe(
    startWith(''),
    map(status => status ? this.filterStatusList(status) : this.allStatuses.slice())
  );

}

filterStatusList(statusName: string) {
return this.allStatuses.filter(status =>
  status.name.toLowerCase().indexOf(statusName.toLowerCase()) === 0);
}

}

1 个答案:

答案 0 :(得分:1)

以下是我的一个看起来像使用反应形式(见下文)。注意表单的formGroup指令。我使用了formControlName指令而不是formControl指令......但要么可以使用。

<强> HTML

    <form class="form-horizontal"
          novalidate
          (ngSubmit)="save()"
          [formGroup]="customerForm">
        <fieldset>
            <div class="form-group">
                <label class="col-md-2 control-label" 
                       for="firstNameId">First Name</label>

                <div class="col-md-8">
                    <input class="form-control" 
                           id="firstNameId" 
                           type="text" 
                           placeholder="First Name (required)" 
                           formControlName="firstName" />
                </div>
            </div>
            <div class="form-group">
                <label class="col-md-2 control-label" 
                    for="lastNameId">Last Name</label>

                <div class="col-md-8">
                    <input class="form-control" 
                           id="lastNameId" 
                           type="text" 
                           placeholder="Last Name (required)" 
                           formControlName="lastName" />
                </div>
            </div>
        </fieldset>
    </form>

组件类

customerForm: FormGroup;

constructor(private fb: FormBuilder) { }

ngOnInit(): void {
    this.customerForm = this.fb.group({
        firstName: ['', [Validators.required, Validators.minLength(3)]],
        lastName: ['', [Validators.required, Validators.maxLength(50)]]
    });

}

此外,如果您需要使用上面的语法引用其中一个FormControl,您可以这样做:

this.customerForm.get('lastName')

您的方法看起来像这样:

this.filteredStatusList = this.myForm.get('status').valueChanges
  .pipe(
    startWith(''),
    map(status => status ? this.filterStatusList(status) : this.allStatuses.slice())
  );