Question

我有以下数据集，即日期时间，坦克和重量。我想为每个罐子和每天添加一个重量小计（根据日期时间对罐子进行分类。

因此，期望的结果将在小计的每个部分的末尾有一行，这将给出第1天的总数，然后是第2天的总数

datum                   tk          gewicht
20/01/2018 9:00         TK1         1000
20/01/2018 10:00        TK1         2000
20/01/2018 4:00         TK10        3000
20/01/2018 8:00         TK2         4000
21/01/2018 6:00         TK3         5000
21/01/2018 7:00         TK5         6000

到目前为止，我的查询得出以下结果：

select cast(datum as datetime) as date, tk, sum(gewicht) as weight
  from tblReclassificatie 
group by rollup(tk,cast(datum as datetime)) 


date                    tk          weight
20/01/2018 9:00         TK1         1000
20/01/2018 10:00        TK1         2000
NULL                    TK1         3000
20/01/2018 4:00         TK10        3000
NULL                    TK10        3000
20/01/2018 8:00         TK2         4000
NULL                    TK2         4000
21/01/2018 6:00         TK3         5000
NULL                    TK3         5000
21/01/2018 7:00         TK5         6000
NULL                    TK5         6000
NULL                    NULL        21000

但顺序错了 - 首先是tk10然后是tk2而不是tk1作为第一个

Answer 1

This query solves my problem (with new id field):

select [Date], tk, weegbon, gewicht, weeklotnr, id from (select [Date], tk, weegbon, sum(gewicht) as gewicht, min(datum) as Datum, min(weeklotnr) as weeklotnr, min(id) as id from (select cast(datum as date) as [Date], datum, tk, weegbon, gewicht, weeklotnr, id from tblReclassificatie )a group by [Date], tk , weegbon with rollup)aa order by Datum, [Date],tk, weegbon

按顺序创建带汇总的小计

1 个答案: