为什么涉及每行结尾的替换会在行的开头添加更多?

时间:2011-01-31 17:39:45

标签: regex perl

我有一些文档,我希望在每行的开头和结尾添加一些内容。原始文档如下所示:

firstLine
secondline

我想把它变成这个:

put 'firstLine';
put 'secondline';

通过使用以下Perl脚本,我只能将其转换为:

put 'firstLine';
';put 'secondline';

似乎在第一行的末尾和第二行的开头有一个$。有人可以帮我弄清楚下面的Perl脚本有什么问题吗?

use File::Find;
use strict;

my ($filename, @lines, $oldterm, $newterm);    #,$File::Find::name);
my $dir = ".";

open MYFILE, ">error.txt" or die $!;
find(\&edits, $dir);

sub edits() {
    $filename = $File::Find::name;
    if (grep(/\.txt$/, $filename)) {           #only process the perl files

        # open the file and read data
        # die with grace if it fails
        open(FILE, "<$filename") or die "Can't open $filename: $!\n";
        @lines = <FILE>;
        close FILE;

        # open same file for writing, reusing STDOUT
        open(STDOUT, ">$filename") or die "Can't open $filename: $!\n";

        # walk through lines, putting into $_, and substitute 2nd away
        for (@lines) {
            s/(&.+)/' "$1" '/ig;
            s/^/put '/ig;
            s/$/';/ig;
            print;
        }

        #Finish up
        close STDOUT;
    }
}

2 个答案:

答案 0 :(得分:8)

根本不使用正则表达式:你已经在@lines数组中分隔了这些行:

for ( @lines ) {
    chomp; # remove newline at the end of the implicit variable $_
    print "puts '$_'\n";
}

答案 1 :(得分:1)

如果你一步到位,你应该有更好的运气。类似的东西:

s/^(&.+)$/put '$1';/im;