Question

我有一个类似to this one的问题。

我需要通过复合键一对一的关系，是否可能？我读过关于this的内容，但它是指一对多的关系

class Header{
    /**
     * 
     * @ORM\Id
     * @ORM\Column(name="UH1", type="integer", nullable=false)
     */
    protected $key1;

    /**
     * 
     * @ORM\Id
     * @ORM\Column(name="UH2", type="integer", nullable=false)
     */
    protected $key2;

    /**
     * @ORM\OneToOne(targetEntity="Detail", mappedBy="header")
     */
    protected $detail;
} 

class Detail{
/**
     * 
     * @ORM\Id
     * @ORM\Column(name="UD1", type="integer", nullable=false)
     */
    protected $key1;

    /**
     * 
     * @ORM\Id
     * @ORM\Column(name="UD2", type="integer", nullable=false)
     */
    protected $key2;

    /**
     * @ORM\OneToOne(targetEntity="Header", inversedBy="detail")
     */
    protected $header;
}

我的意思是每个实体有两列作为Id ...我需要添加the joincolumn吗？

Answer 1

您需要使用JoinColumns注释，该注释允许定义JoinColumn注释数组，以处理ManyToOne或OneToOne关联的此类情况。

使用以下实体：

的appbundle \实体\ a.php只会

namespace AppBundle\Entity;

use Doctrine\ORM\Mapping as ORM;

/**
 * @ORM\Entity()
 */
class A
{
    /**
     * @ORM\Id
     * @ORM\Column(name="key1", type="integer", nullable=false)
     */
    private $key1;

    /**
     * @ORM\Id
     * @ORM\Column(name="key2", type="integer", nullable=false)
     */
    private $key2;

    /**
     * @ORM\OneToOne(targetEntity="AppBundle\Entity\B", mappedBy="a")
     * @ORM\JoinColumns(
     *      @ORM\JoinColumn(name="key1", referencedColumnName="key1"),
     *      @ORM\JoinColumn(name="key2", referencedColumnName="key2"),
     * )
     */
    private $b;
}

的appbundle \实体\ B.php

namespace AppBundle\Entity;

use Doctrine\ORM\Mapping as ORM;

/**
 * @ORM\Entity()
 */
class B
{
    /**
     * @ORM\Id
     * @ORM\Column(name="key1", type="integer", nullable=false)
     */
    private $key1;

    /**
     * @ORM\Id
     * @ORM\Column(name="key2", type="integer", nullable=false)
     */
    private $key2;

    /**
     * @ORM\OneToOne(targetEntity="AppBundle\Entity\A", inversedBy="b")
     * @ORM\JoinColumns(
     *      @ORM\JoinColumn(name="key1", referencedColumnName="key1"),
     *      @ORM\JoinColumn(name="key2", referencedColumnName="key2"),
     * )
     */
    private $a;
}

我可以达到理想的行为。当被要求进行架构更新时，Doctrine输出：

CREATE TABLE a (key1 INT NOT NULL, key2 INT NOT NULL, UNIQUE INDEX b_uniq (key1, key2), PRIMARY KEY(key1, key2)) DEFAULT CHARACTER SET utf8 COLLATE utf8_unicode_ci ENGINE = InnoDB;
CREATE TABLE b (key1 INT NOT NULL, key2 INT NOT NULL, UNIQUE INDEX a_uniq (key1, key2), PRIMARY KEY(key1, key2)) DEFAULT CHARACTER SET utf8 COLLATE utf8_unicode_ci ENGINE = InnoDB;
ALTER TABLE a ADD CONSTRAINT FK_E8B7BE432C5C6450B55535EA FOREIGN KEY (key1, key2) REFERENCES b (key1, key2);
ALTER TABLE b ADD CONSTRAINT FK_71BEEFF92C5C6450B55535EA FOREIGN KEY (key1, key2) REFERENCES a (key1, key2);

Doctrine 2通过两个实体的复合键一对一

1 个答案: