在oracle中使用asc顺序将行转换为列

Question

 SELECT * FROM 
  ( 
    SELECT TEST_NAME, SBNO, VAL
    FROM TABLE1

  ) 
  PIVOT ( 
    MAX(VAL) 
  FOR SBNO in (1 value1, 2 value2, 3 value3 ));

输出：

我想按升序显示数据，如下所示：

2.3,2.4,2.5

但结果是

2.3,2.5,2.4

Answer 1

这样就可以了。我创建了一个新的SBNO列，按test_name和value排序，然后PIVOT运算符将完成剩下的工作。

;with cte as (
    select
        test_name
        ,val
        ,'Value' + cast(ROW_NUMBER() over (partition by test_name order by test_name, val) as varchar(5)) as new_SBNO
    from TABLE1
)
select *
from cte
pivot (
    max(val)
    for new_SBNO in (value1, value2, value3)
) pvt

Answer 2

我会使用条件聚合来做到这一点：

select test_name,
       max(case when seqnum = 1 then val end) as value_1,
       max(case when seqnum = 2 then val end) as value_2,
       max(case when seqnum = 3 then val end) as value_3
from (select t1.*,
             row_number() over (partition by test_name order by val asc) as seqnum
      from table1 t1
     ) t1
group by test_name;

您可以使用pivot表达此信息。在Oracle中，pivot甚至可以更快一些。我发现条件聚合更灵活，更易于实现。