Question

我有一个像[3,9,14]的列表，我正在尝试创建一个嵌套列表，使用[3,9,14]的值作为每个嵌套列表increment 1 each step的开头，直到它到达{{ 1}}，这样最终的嵌套列表看起来像next end point - 1。最好的方法是什么？

Answer 1

>>> nums = [3,9,14]
>>> [list(range(x,y)) for x, y in  zip([0] + nums, nums)]
[[0, 1, 2], [3, 4, 5, 6, 7, 8], [9, 10, 11, 12, 13]]

Answer 2

>>> nums = [3,9,14]
>>> [list(g) for g in map(range, [0] + nums, nums)]
[[0, 1, 2], [3, 4, 5, 6, 7, 8], [9, 10, 11, 12, 13]]

Answer 3

l=[3,9,14]
data=[]
x=0
for i in l:
    data.append(list(range(x,i)))
    x=i
print(data)

Answer 4

试试这个。

inputdata  = [3,9,14]
outputdata = []
a =[]
b =[]
for i,value in enumerate(inputdata):
    if i == 0:
        a.append(value)
    else:
        a.append(value-inputdata[i-1])
for i,value in enumerate(a):
    if i == 0:
        data = [x for x in range(value)]
        b.append(data)
    else:
        data = [x for x in range(value,inputdata[i])]
        b.append(data)

Answer 5

L = [3, 9, 14]
result = []
sub_list = []
counter = 0

for i in L:
    sub_list = []
    for j in range(counter, i):
        sub_list.append(counter)
        counter += 1
    counter = i
    result.append(sub_list)

print(result)

Answer 6

您可以尝试这样的事情：

list_a=[3,9,14]
list_a.insert(0,0)
for i in range(0,len(list_a),1):
    chunk=list_a[i:i+2]
    if len(chunk)==2:
        print(list(range(chunk[0],chunk[1])))

输出：

[0, 1, 2]
[3, 4, 5, 6, 7, 8]
[9, 10, 11, 12, 13]

根据整数列表创建嵌套的范围列表

6 个答案: