Question

我想在UIScrollView中切换七个按钮当我点击一个按钮（标签= 1）时，它会突出显示。然后我点击另一个按钮（tag = 2），它会突出显示并取消突出显示按钮（标记= 1）如何控制它们？
感谢。

for i in 1...7 {
        customButton = customButton(frame: CGRect(x: 0, y: 0, width: 100, height: 60))
        customButton?.tag = i
        customButton?.center = CGPoint(x: (-50)+(CGFloat(i)*100), y: 30)

        customButton?.addTarget(self, action: #selector(buttonClick(sender:)), for: .touchUpInside)
        scrollView.addSubview(customButton!)
 }

@objc func buttonClick(sender: UIButton) {

    //how to highlight clicked button and unhighlight other buttons

    switch sender.tag {
        case 1:
            break
        case 2:
            break
        case 3:
            break
        case 4:
            break
        case 5:
            break
        case 6:
            break
        case 7:
            break
        default:
            break
}

Answer 1

这个for循环将遍历scrollView的所有子视图。它通过比较isHighlighted对象来更改sender属性。

@objc func buttonClick(sender: UIButton) {
    for case let button as UIButton in scrollView.subviews
    {
      button.isHighlighted = sender == button
    }
}

Answer 2

创建所有按钮的插座集合并提供标签

为所有按钮设置相同的操作

 class MyViewController: UIViewController {

    // collection of uibutton
    @IBOutlet var barItems: [UIButton]!

    var selectedItem: Int? { // setting nil will deselect all item
         set {
               barItems.forEach { (button) in
                  let isSelected = button.tag == newValue
                  button.isSelected = isSelected
               }
         }
         get {
               return barItems.first(where: {$0.isSelected})?.tag
         }
    }

    // Same action for all button
    @IBAction func onItemClick(_ sender: UIButton) {
         selectedItem = sender.tag
     }
  }

如何控制多个按钮，只有一个按钮是由swift4高亮？

2 个答案: