Question

我有2个单独的列，＆＃39; ATFTE＆＃39;和＆＃39; SATFTE＆＃39;。使用这两列，我必须执行除法并将结果存储在单独的列中（比如金字塔）。我正在尝试使用isnull函数，因为在许多情况下，分母为0并将其带入子查询中。它显示错误 - ＆＃39;无效的列名称＆＃39; - ATFTE和SATFTE。我怎样才能纠正它？

select isnull(ATFTE/SATFTE,0) as Pyramid
from dw_UtilizationPredictionReport
where WFMGrade in (
select WFMGrade,
    case 
        when WFMGrade IN ('P/PA','PAT','A') then sum(TotalFTE)
        else 0
    END as ATFTE,
    case
        when WFMGrade IN ('SA','M','SM','AD','D','SD','AVP','VP','SVP','EVP') 
        and WFMGrade NOT IN ('Cont') then sum(TotalFTE)
        else 0
    END as SATFTE
from dw_UtilizationPredictionReport
group by (WFMGrade)
)

Answer 1

试试这个：

select  CASE WHEN ISNULL(SATFTE,0) = 0 THEN 0
    ELSE ISNULL(ATFTE/SATFTE,0) 
    END AS Pyramid FROM
(select WFMGrade,
    case 
        when WFMGrade IN ('P/PA','PAT','A') then sum(TotalFTE)
        else 0
    END as ATFTE,
    case
        when WFMGrade IN ('SA','M','SM','AD','D','SD','AVP','VP','SVP','EVP') 
        and WFMGrade NOT IN ('Cont') then sum(TotalFTE)
        else 0
    END as SATFTE
from dw_UtilizationPredictionReport
group by (WFMGrade)) as tbl

在您的查询中，您似乎已经犯了以下错误：

您不能在WHERE中使用带有多个列的IN语句子句。
ATFTE / SATFTE不是表格的列 “dw_UtilizationPredictionReport”，所以你不能在它中使用它选择。

Answer 2

select a.WFMGrade, sum(b.TotalFTE) / sum(c.(TotalFTE)
from dw_UtilizationPredictionReport a
left join dw_UtilizationPredictionReport b 
on b.WFMGrade = a.WFMGrade 
and b.WFMGrade IN ('P/PA','PAT','A')
left join dw_UtilizationPredictionReport c 
on c.WFMGrade = a.WFMGrade 
and c.WFMGrade IN ('SA','M','SM','AD','D','SD','AVP','VP','SVP','EVP') 
group by a.WFMGrade

如果这对您有效，请尝试不必包含条件＆＃34;续＆＃34;因为你有条件。

Answer 3

尝试第一位

SELECT 
    CASE 
        WHEN ISNULL(SATFTE,0) = 0 THEN 0 -- Or whatever you want
        ELSE ISNULL(ATFTE/SATFTE,0) 
    END AS Pyramid

使用isnull（）函数和子查询

3 个答案: