Question

你好每一个我都难以从我的插入代码中找到我的复选框值

HTML

<div class="form-group">
                    <label class="col-md-4 control-label">You are in :</label>
                    <div class="col-md-4">
      <input name="lgan[]" type="checkbox"  value="Hr-high"><label>Hr(High)</label><br>
                <input name="lgan[]" type="checkbox"  value="Pr-high"><label>Pr(High)</label><br>
                <input name="lgan[]" type="checkbox"  value="Fr-high"><label>Fr(High)</label><br>
                <input name="lgan[]" type="checkbox"  value="secretary-high"><label>secretary(High)</label><br>
                <input name="lgan[]" type="checkbox"  value="media-high"><label>media(High)</label><br>
                </br>
                <input name="lgan[]" type="checkbox"  value="gwala-high"    > <label>جوالة الخير(High)</label><br>

                <input name="lgan[]" type="checkbox"  value="mogtm3ia-high"  >   <label>الخدمة المجتمعية(High)</label><br>
                <button type="submit" name="log" class="btn btn-warning" >Send <span class="glyphicon glyphicon-send"></span></button>

                    </div>
                </div>

我的php代码是

<?php
if(isset($_POST["log"])){
    $formok=TRUE;
    $new_id = mysqli_insert_id($link);
        if (!empty ($_POST['lgan'])){
             foreach ($_POST['lgan'] as $value){
                $res1 = mysqli_query($link,"INSERT INTO `lgan`(`ID1`,`lgan`) 
                  VALUES ('$new_id','$value')");
echo mysqli_error($link); }}}
?>

this is my phpmyadmin database ID1 is an forign key from another table

我尝试使用此代码来检索数据但我的页面中没有任何内容

<?php
ini_set('display_errors', 1); ini_set('display_startup_errors', 1); 
error_reporting(E_ALL);

include ("../../../connection.php");
if(!empty($_SESSION["username"]) and $_SESSION["id"] !=""){
}else{
header('location:login.php');
}

$select1 = "select lgan from lgan where ID1='".$_GET["id"]."'";
$results1 = mysqli_query($link,$select1);
$row = mysqli_fetch_array($results1);

 print_r ($row); 

?>
            <br>    <input name="lgan[]" type="checkbox"  value="Hr-high"  
<?php if (in_array("Hr-high",$row)) { echo " checked"; }?> ><label>Hr(High)
</label><br>
                <input name="lgan[]" type="checkbox"  value="Pr-high"  <?php 
if (in_array("Pr-high",$row)) { echo " checked"; }?> ><label>Pr(High)
</label><br>
                <input name="lgan[]" type="checkbox"  value="Fr-high"  <?php 
if (in_array("Fr-high",$row)) { echo " checked"; }?> ><label>Fr(High)
</label><br>
<?php

?>

that is the output

它会调查3个复选框！我该怎么办？

从mysql中检索复选框值时出错

0 个答案: