由其他函数

Question

刚开始编程（关于堆栈溢出的第一篇文章），并通过Python中最基本的东西。我尝试尽可能多地完成练习，以便更好地理解它是如何工作的。

最新的练习是制作游戏Tic Tac Toe。我终于通过大量的谷歌搜索得到了代码，但我不确定我错过了关于用作函数'draw（）'的参数的局部变量。从我的代码的第一行可以看出，我必须导入模块副本并使用copy.deepcopy（）从列表'board'中定义此函数内的局部变量。

函数'draw（）'是从'play_game（）'调用的，但没有复制列表变量'board'，我最终覆盖了所有其他函数的列表。这导致程序的所有其他部分出错。

我错过了什么？对我的代码的任何其他评论都是最受欢迎的。

import copy
def draw(board):
    #Draws the board game and converts numbers from game board list to X and O's
    print()
    bo = copy.deepcopy(board)
    for i in range(3):
        for b in range(3):
            if bo[i][b] == 1:
                bo[i][b] = "X"
            elif bo[i][b] == 2:
                bo[i][b] = "O"
            else:
                bo[i][b] = " "
    for i in range(3):
        print(" ---" * 3)
        print("| %s | %s | %s |" % (bo[i][0], bo[i][1], bo[i][2]), end="\n")
    print(" ---" * 3)

def winner(board):
    # Checkis if there's a diagonal winner
    if (board[0][0] == board[1][1] == board[2][2]) and board[1][1] != 0:
        return board[1][1]
    elif (board[0][2] == board[1][1] == board[2][0]) and board[1][1] != 0:
        return board[1][1]
    else:
        for i in range(3):
            #Checks if there's a winner in a row
            if (board[i][0] == board[i][1] == board[i][2]) and board[i][i] != 0:
                return board[i][i]
            #Checks if there's a winner in a column
            elif (board[0][i] == board[1][i] == board[2][i]) and board[i][i] != 0:
                return board[i][i]
    return 0

def player_input(board, turn):
    print("Enter a coordinate (row,column) for your choice, eg. '2,3'")
    while True:
        player = input("Player " + str(turn) + ": ")
        try:
            cor = player.split(",")
            row = int(cor[0]) - 1
            col = int(cor[1]) - 1
            if board[row][col] == 0:
                board[row][col] = turn
                return board
            else:
                print("This space is allready occupied, please choose another coordinate.")
        except:
            print("Your choice raised an error, please try again.")

def play_again():
    play = input("This was fun! Play again? (y/n): ")
    if play == "y":
        return True
    else:
        return False

def player_turn(turn):
    # Returns what player is to go next
    if turn == 1:
        return 2
    else:
        return 1

def play_game():
    # This method run all other functions in a single gameplay, and exits when the game is over
    # Set all initial variables used in a new game
    game = [[0,0,0],[0,0,0],[0,0,0]]
    turn = 1
    count = 0
    win = 0
    while True:
        draw(game)
        game = player_input(game, turn)
        count += 1
        win = winner(game)
        if count == 9 and win == 0:
            print("It's a draw!")
            return
        elif win != 0:
            print("Player " + str(win) + " won!")
            return
        turn = player_turn(turn)

if __name__ == "__main__":
    ''' This is the game Tic, Tac, Toe. When run as a standalone script the game will
        be initialized from the main method. When game is over the user will be prompted
        to play again... '''
    print("\n\n" + "----------     WELCOME TO TIC, TAC TOE. LET'S PLAY!     ----------\n\n")
    play = True

    while play:
        play_game()
        play = play_again()