如何使用PHP通过FTP连接检查远程服务器上是否存在特定文件?
答案 0 :(得分:49)
一些建议:
ftp_size
,如果不存在则返回-1:http://www.php.net/manual/en/function.ftp-size.php fopen
,例如fopen(“ftp://user:password@example.com/somefile.txt”,“r”)ftp_nlist
,检查您想要的文件名是否在列表中:http://www.php.net/manual/en/function.ftp-nlist.php 答案 1 :(得分:31)
我使用它,更容易一些:
// the server you wish to connect to - you can also use the server ip ex. 107.23.17.20
$ftp_server = "ftp.example.com";
// set up a connection to the server we chose or die and show an error
$conn_id = ftp_connect($ftp_server) or die("Couldn't connect to $ftp_server");
ftp_login($conn_id,"ftpserver_username","ftpserver_password");
// check if a file exist
$path = "/SERVER_FOLDER/"; //the path where the file is located
$file = "file.html"; //the file you are looking for
$check_file_exist = $path.$file; //combine string for easy use
$contents_on_server = ftp_nlist($conn_id, $path); //Returns an array of filenames from the specified directory on success or FALSE on error.
// Test if file is in the ftp_nlist array
if (in_array($check_file_exist, $contents_on_server))
{
echo "<br>";
echo "I found ".$check_file_exist." in directory : ".$path;
}
else
{
echo "<br>";
echo $check_file_exist." not found in directory : ".$path;
};
// output $contents_on_server, shows all the files it found, helps for debugging, you can use print_r() as well
var_dump($contents_on_server);
// remember to always close your ftp connection
ftp_close($conn_id);
使用的功能:(感谢middaparka)
使用in_array查看该文件是否存在于数组中
答案 2 :(得分:10)
只需检查文件的大小即可。如果尺寸为-1
,则不存在,所以:
$file_size = ftp_size($ftp_connection, "example.txt");
if ($file_size != -1) {
echo "File exists";
} else {
echo "File does not exist";
}
如果大小为0
,则文件确实存在,它只是0个字节。
答案 3 :(得分:5)
这是@JohanPretorius解决方案的优化,以及对@Andrew等的“大型目录的缓慢和低效”的评论的答案:如果您需要多个“file_exist check”,此功能是最佳解决方案。
ftp_file_exists()
缓存最后一个文件夹 function ftp_file_exists(
$file, // the file that you looking for
$path = "SERVER_FOLDER", // the remote folder where it is
$ftp_server = "ftp.example.com", //Server to connect to
$ftp_user = "ftpserver_username", //Server username
$ftp_pwd = "ftpserver_password", //Server password
$useCache = 1 // ALERT: do not $useCache when changing the remote folder $path.
){
static $cache_ftp_nlist = array();
static $cache_signature = '';
$new_signature = "$ftp_server/$path";
if(!$useCache || $new_signature!=$cache_signature)
{
$useCache = 0;
//$new_signature = $cache_signature;
$cache_signature = $new_signature;
// setup the connection
$conn_id = ftp_connect($ftp_server) or die("Error connecting $ftp_server");
$ftp_login = ftp_login($conn_id, $ftp_user, $ftp_pwd);
$cache_ftp_nlist = ftp_nlist($conn_id, $path);
if ($cache_ftp_nlist===FALSE)die("erro no ftp_nlist");
}
//$check_file_exist = "$path/$file";
$check_file_exist = "$file";
if(in_array($check_file_exist, $cache_ftp_nlist))
{
echo "Found: ".$check_file_exist." in folder: ".$path;
}
else
{
echo "Not Found: ".$check_file_exist." in folder: ".$path;
};
// use for debuging: var_dump($cache_ftp_nlist);
if(!$useCache) ftp_close($conn_id);
} //function end
//Output messages
echo ftp_file_exists("file1-to-find.ext"); // do FTP
echo ftp_file_exists("file2-to-find.ext"); // using cache
echo ftp_file_exists("file3-to-find.ext"); // using cache
echo ftp_file_exists("file-to-find.ext","OTHER_FOLDER"); // do FTP
答案 4 :(得分:4)
一般解决方案是:
使用in_array查看该文件是否存在于ftp_rawlist返回的数组中
也就是说,如果您有相关的URL包装器,则可以简单地使用file_exists。 (有关详细信息,请参阅PHP FTP and FTPS protocols and wrappers manual page。)
答案 5 :(得分:1)
您可以使用ftp_nlist列出远程服务器上的所有文件。然后你应该搜索结果数组来检查你正在寻找的文件是否存在。