我使用带有salt和IV的AES来加密和解密一个唯一的ID,但是在解密时它给出了javax.crypto.BadPaddingException。
解密数据时每次都给出完整的错误堆栈跟踪
javax.crypto.BadPaddingException: Given final block not properly padded null
at com.sun.crypto.provider.CipherCore.doFinal(CipherCore.java:991)
at com.sun.crypto.provider.CipherCore.doFinal(CipherCore.java:847)
at com.sun.crypto.provider.AESCipher.engineDoFinal(AESCipher.java:446)
at javax.crypto.Cipher.doFinal(Cipher.java:2165)
at com.data.commons.security.impl.DataAESCrypt.decode(DataAESCrypt.java:84)
at com.data.CryptoTest.main(CryptoTest.java:13)
加密方法 -
private static final int PASSWORD_ITERATIONS = 65536;
private static final int KEY_LENGTH = 256;
private static byte[] salt = new byte[16];
private static byte[] iv= new byte[16];
private static final String ALGORITHM = "AES/CBC/PKCS5Padding" ;
@Override
public String encode(String plainText) throws Exception {
// TODO Auto-generated method stub
try {
SecureRandom random = new SecureRandom();
random.nextBytes(salt);
SecretKeyFactory factory = SecretKeyFactory.getInstance("PBKDF2WithHmacSHA1");
KeySpec spec = new PBEKeySpec(plainText.toCharArray(), salt, PASSWORD_ITERATIONS, KEY_LENGTH);
SecretKey tmp = factory.generateSecret(spec);
SecretKey secret = new SecretKeySpec(tmp.getEncoded(), "AES");
Cipher cipher = Cipher.getInstance(ALGORITHM);
AlgorithmParameters params = cipher.getParameters();
iv = params.getParameterSpec(IvParameterSpec.class).getIV();
cipher.init(Cipher.ENCRYPT_MODE, secret);
byte[] encryptedText = cipher.doFinal(plainText.getBytes("UTF-8"));
ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
outputStream.write(salt);
outputStream.write(iv);
outputStream.write(encryptedText);
System.out.println("Salt " + DatatypeConverter.printBase64Binary(salt) + " IV " + DatatypeConverter.printBase64Binary(iv) );
return DatatypeConverter.printBase64Binary(outputStream.toByteArray());
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
解密方法
public String decode(String encodedText) throws Exception {
// TODO Auto-generated method stub
try {
byte[] ciphertext = DatatypeConverter.parseBase64Binary(encodedText);
if (ciphertext.length < 48) {
return null;
}
byte[] salt = Arrays.copyOfRange(ciphertext, 0, 16);
byte[] iv = Arrays.copyOfRange(ciphertext, 16, 32);
byte[] ct = Arrays.copyOfRange(ciphertext, 32, ciphertext.length);
System.out.println("Salt " + DatatypeConverter.printBase64Binary(salt) + " IV " + DatatypeConverter.printBase64Binary(iv) );
SecretKeyFactory factory = SecretKeyFactory.getInstance("PBKDF2WithHmacSHA1");
KeySpec spec = new PBEKeySpec(encodedText.toCharArray(), salt, PASSWORD_ITERATIONS, KEY_LENGTH);
SecretKey tmp = factory.generateSecret(spec);
SecretKey secret = new SecretKeySpec(tmp.getEncoded(), "AES");
Cipher cipher = Cipher.getInstance(ALGORITHM);
cipher.init(Cipher.DECRYPT_MODE, secret, new IvParameterSpec(iv));
byte[] plaintext = cipher.doFinal(ct);
return new String(plaintext, "UTF-8");
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
我是JCA的新手。
答案 0 :(得分:1)
您在plainText.toCharArray()
中使用encodedText.toCharArray()
和PBEKeySpec
作为密码。相反,请使用实际的密码。目前,只有在您知道明文消息时才能获取纯文本消息,这并不是很有用。用编码的密文作为输入对其进行解密肯定不起作用。