使用我的电子表格,我有2张Google表格与2张相关联。当表单被提交时,脚本会执行并执行它的操作。但是,我只希望脚本基于单个工作表的提交来执行。就像现在一样,当任何一个表单被提交时脚本都会执行。
我的两张纸是: 工作提交 和订单提交
有什么建议吗?
// Work Order
// Get template from Google Docs and name it
var docTemplate = ""; // *** replace with your template ID ***
var docName = "Work Order";
var printerId = "";
function addDates() {
var date = new Date(); // your form date
var holiday = ["09/04/2017","10/09/2017","11/23/2017","12/24/2017","12/25/2017","01/01/2018"]; //Define holiday dates in MM/dd/yyyy
var days = 5; //No of days you want to add
date.setDate(date.getDate());
var counter = 0;
if(days > 0 ){
while (counter < days) {
date.setDate(date.getDate() + 1 );
var check = date.getDay();
var holidayCheck = holiday.indexOf(Utilities.formatDate(date, "EDT", "MM/dd/yyyy"));
if (check != 0 && check != 6 && holidayCheck == -1) {
counter++;
}
}
}
Logger.log(date) //for this example will give 08/16/2017
return date;
}
function createNewDoc(values) {
//Get information from form and set as variables
var email_address = "";
var job_name = values[1];
var order_count = values[2];
var order_form = values[7];
var print_services = values[3];
var priority = values[5];
var notes = values[6];
var formattedDate = Utilities.formatDate(new Date(), "EDT", "MM/dd/yyyy");
var expirationDate = Utilities.formatDate(addDates(), "EDT", "MM/dd/yyyy");
// Get document template, copy it as a new temp doc, and save the Doc's id
var copyId = DriveApp.getFileById(docTemplate)
.makeCopy(docName+' for '+job_name)
.getId();
// Open the temporary document
var copyDoc = DocumentApp.openById(copyId);
// Get the document's body section
var copyBody = copyDoc.getActiveSection();
// Replace place holder keys,in our google doc template
copyBody.replaceText('keyJobName', job_name);
copyBody.replaceText('keyOrderCount', order_count);
copyBody.replaceText('keyOrderForm', order_form);
copyBody.replaceText('keyPrintServices', print_services);
copyBody.replaceText('keyPriority', priority);
copyBody.replaceText('keyNotes', notes);
copyBody.replaceText('keyDate', formattedDate);
copyBody.replaceText('keyDue', expirationDate);
// Save and close the temporary document
copyDoc.saveAndClose();
// Convert temporary document to PDF by using the getAs blob conversion
var pdf = DriveApp.getFileById(copyId).getAs("application/pdf");
// Attach PDF and send the email
var subject = "New Job Submission - " + job_name;
var body = "Here is the work order for " + job_name + ". Job is due " + expirationDate + ".";
MailApp.sendEmail(email_address, subject, body, {htmlBody: body, attachments: pdf});
// Move file to folder
var file = DriveApp.getFileById(copyId);
DriveApp.getFolderById("").addFile(file);
file.getParents().next().removeFile(file);
var newDocName = docName + ' for ' + job_name;
return [copyId, newDocName];
}
function printGoogleDocument(copyId, docName) {
// For notes on ticket options see https://developers.google.com/cloud-print/docs/cdd?hl=en
var ticket = {
version: "1.0",
print: {
color: {
type: "STANDARD_COLOR"
},
duplex: {
type: "NO_DUPLEX"
},
}
};
var payload = {
"printerid" : "",
"content" : copyId,
"title" : docName,
"contentType" : "google.kix", // allows you to print google docs
"ticket" : JSON.stringify(ticket),
};
var response = UrlFetchApp.fetch('https://www.google.com/cloudprint/submit', {
method: "POST",
payload: payload,
headers: {
Authorization: 'Bearer ' + GoogleCloudPrint.getCloudPrintService().getAccessToken()
},
"muteHttpExceptions": true
});
// If successful, should show a job here: https://www.google.com/cloudprint/#jobs
response = JSON.parse(response);
if (response.success) {
Logger.log("%s", response.message);
} else {
Logger.log("Error Code: %s %s", response.errorCode, response.message);
}
return response;
}
// When Form Gets submitted
function onFormSubmit(e) {
var values = e.values;
var returnedDocValues = createNewDoc(values);
var copyId = returnedDocValues[0];
var docName= returnedDocValues[1];
printGoogleDocument(copyId, docName);
}
编辑: 我不确定如何做一个完整或可验证的例子,因为它依赖于表单提交。我不经常使用javascript,所以我还在学习。
无论如何,我更新了我的onFormSubmit函数,但是,我的其他函数无法执行。该脚本无法创建文档,反过来也无法发送到Google云端打印
// When Form Gets submitted
function onFormSubmit(e) {
// Initialize
var rng = e.range;
var sheet = rng.getSheet();
var name = sheet.getName();
// If the response was not submitted to the right sheet, exit.
if(name != "Job Submission") return;
var values = e.values;
var returnedDocValues = createNewDoc(values);
var copyId = returnedDocValues[0];
var docName= returnedDocValues[1];
printGoogleDocument(copyId, docName);
}
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答案 0 :(得分:4)
如果onFormSubmit函数位于绑定到电子表格的脚本上,则事件对象包含范围对象。您可以使用getSheet获取工作表,然后使用getName获取工作表名称。
示例:
function onFormSubmit(e){
// Initialize
var rng = e.range;
var sheet = rng.getSheet();
var name = sheet.getName();
// If the response was not submitted to the right sheet, exit.
if(name != "Responses 1") return;
//Otherwise continue
}
答案 1 :(得分:0)
脱离鲁本的建议,这就是我最终的结果
var Manager_User = function(mgr, usrs) {
return {
manager: mgr,
usrs: usrs,
addUser: function(mgr, usr) {
usrs.push(usr);
},
removeUser: function(index) {
usrs.splice(index, 1);
}
}
}
var mgrUser = new Manager_User("x", ["a", "b", "c"]);
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