Question

我有这个代码用它们各自的src替换字符串中的图像标签..

$url='<img class="emojioneemoji" src="http://localhost/sng/assets/js/plugins/em/2.1.4/assets/png/1f602.png">checking<img class="emojioneemoji" src="http://localhost/sng/assets/js/plugins/em/2.1.4/assets/png/1f601.png"><img class="emojioneemoji" src="http://localhost/sng/assets/js/plugins/em/2.1.4/assets/png/1f62c.png">working check<img class="emojioneemoji" src="http://localhost/sng/assets/js/plugins/em/2.1.4/assets/png/1f600.png">';


$doc = new DOMDocument();
        @$doc->loadHTML($url);

        $tags = $doc->getElementsByTagName('img');
        $str = "-" ;
        foreach ($tags as $tag) {
         $img_path =  $tag->getAttribute('src');
         $directory = $img_path;
         $ee = pathinfo($directory);
         $pic_name=  $ee['basename'];
         $next = "" ;
         if ($tag->nextSibling && get_class($tag->nextSibling) == "DOMText") {
            $next = $tag->nextSibling->wholeText . "-" ;
         }
         $str .= $pic_name . "-" . $next ;
        }
        echo  $str ;

以上代码的输出是

-1f602.png-checking-1f601.png-1f62c.png-working check-1f600.png-

现在我该如何替换＆＃34;中包含的图像src？ - ＆＃34;到上面的完整图片标签？

Answer 1

您可以将值存储在数组中。现在你可以使用这个数组来做进一步的工作。

$url='<img class="emojioneemoji" src="http://localhost/sng/assets/js/plugins/em/2.1.4/assets/png/1f602.png">checking<img class="emojioneemoji" src="http://localhost/sng/assets/js/plugins/em/2.1.4/assets/png/1f601.png"><img class="emojioneemoji" src="http://localhost/sng/assets/js/plugins/em/2.1.4/assets/png/1f62c.png">working check<img class="emojioneemoji" src="http://localhost/sng/assets/js/plugins/em/2.1.4/assets/png/1f600.png">';


$doc = new DOMDocument();
@$doc->loadHTML($url);

$tags = $doc->getElementsByTagName('img');
$str = [] ;
$i = 0;

foreach ($tags as $tag) {
    $img_path =  $tag->getAttribute('src');
    $directory = $img_path;
    $ee = pathinfo($directory);
    $pic_name=  $ee['basename'];
    $next = "" ;
    if ($tag->nextSibling && get_class($tag->nextSibling) == "DOMText") {
        $next = $tag->nextSibling->wholeText;
    }

    array_push($str, ['src' => $pic_name, 'next' => $next]);
}

echo "<pre>";
print_r($str);

用string中的完整图像标记替换image src

1 个答案: