我正在尝试使用Microsoft Graph API将用户分配给任务来访问Planner。 当我没有尝试分配某人时,我的代码工作正常(通过省略assignments
部分),但当我添加分配部分(following the template here)时,我得到了一个BadRequest
错误回复。
{ “错误”:{ “代码”:“”, “message”:“请求无效:\ r \ nValue不能为空。\ r \ nParameter name:qualifiedName”, “innerError”:{ “request-id”:“......”, “日期”:“2018-01-30T12:23:59” } } }
public TaskResponse CreateTask(string planId, string bucketId, string title, Dictionary<string, Assignment> assignments = null, DateTime? dueDateTime = null)
{
RestRequest TaskRequest = new RestRequest("planner/tasks", Method.POST)
{
RequestFormat = DataFormat.Json
};
Dictionary<string, object> assignees = new Dictionary<string, object>();
foreach(string assignment in assignments.Keys)
{
assignees.Add(assignment, new
{
});
}
var body = new
{
planId,
bucketId,
title,
assignments = assignees,
dueDateTime
};
TaskRequest.AddParameter("application/json", JsonConvert.SerializeObject(body), "application/json", ParameterType.RequestBody);
IRestResponse TaskResponse = GraphClient.Execute(TaskRequest);
if (!TaskResponse.IsSuccessful)
{
return null;
}
var result = JsonConvert.DeserializeObject<TaskResponse>(TaskResponse.Content);
return result;
}
如果有人知道为什么回复表明我没有提供文档中从未提及的参数,我会很感激......
答案 0 :(得分:1)
我设法通过使用适当的类而不是匿名类型来解决这个问题。通过这样做,我能够使用@odata.type
注释该属性,这不能作为变量名称接受。
public class NewAssignment
{
[JsonProperty("@odata.type")]
public string ODataType { get; set; }
[JsonProperty("orderHint")]
public string OrderHint { get; set; }
public NewAssignment()
{
ODataType = "#microsoft.graph.plannerAssignment";
OrderHint = " !";
}
}
这允许我使用以下代码:
Dictionary<string, object> assignees = new Dictionary<string, object>();
foreach (string assignment in assignments.Keys)
{
assignees.Add(assignment, new NewAssignment());
}
var body = new
{
planId,
bucketId,
title,
assignments = assignees,
dueDateTime
};