Question

我有一个充满字符串的数据集，我想分开包含Dates的字符串我编写了以下正则表达式来提取它们：

print (re.findall(r'[Jan(uary)?|Feb(ruary)?|Mar(ch)?||April|May|Jun(e)?|Jul(y)?|Aug(ust)?|Sep(tember)?|Oct(ober)?|Nov(ember)?|Dec(ember)?]+\s\d+', x))

其中x表示正在处理的字符串。我想获得以下格式：例如：

December 2018
Feb 11-12
Feb 12-Mar 21
3rd Jan
February 12

然而，还提取了一些额外的字符串。像：

"Of 2017" from the string "BEST OF 2017"

"Line 1" from the string "Line 1"

"'addington 2" & "Paddington 2" from string "Paddington 2"

'hopping 3', 'as 20'

如何修复这些错误？

Answer 1

你正在寻找的正则表达式有点复杂：

^(\d{1,2}\w{2} )?((Jan(uary)?|Feb(ruary)?|Mar(ch)?|April|May|Jun(e)?|Jul(y)?|Aug(ust)?|Sep(tember)?|Oct(ober)?|Nov(ember)?|Dec(ember)?)[- \d]*)+$

Here's a full test

Answer 2

在https://regex101.com/进行了测试，按预期工作

/Jan(uary)?|Feb(ruary)?|Mar(ch)?|April|May|Jun(e)?|Jul(y)?|Aug(ust)?|Sep(tember)?|Oct(ober)?|Nov(ember)?|Dec(ember)?]+\s\d+/

用于提取用户定义日期格式的正则表达式

2 个答案: