我正在使用此代码$json_output = (json_decode($json, true));
从JSON转换为PHP中的关联数组。
生成的数组对我来说太难了,我需要只打印一些键和值,但它们是嵌套的,到目前为止我还没能做到,我打印的例子对于这个来说太基本了
这是我的JSON的一部分:
{
"project": {
"company": "Company Name SA de CV",
"name": "Project Name",
"files": [
{
"project-id": "666666",
"filenameOnDisk": "HH-ORG-CMD-GUI-File.docx",
"uploaded-date": "2018-01-29T21:20:56Z",
"private": "0",
"version-id": "3939061",
"status": "active",
"tags": [
{
"name": "OPD",
"id": "25047",
"color": "#9e6957"
}
],
"id": "3796128",
"last-changed-on": "2018-01-29T21:21:46Z",
"versions": [],
"uploaded-by-user-first-name": "Someone",
"uploaded-by-user-last-name": "Anything",
"name": "HH-ORG-CMD-GUI-GUIA_RAPIDA_PARA_CREAR_PROCESOS",
"size": "262747",
"category-name": "Instructivos"
},
{
"project-id": "666",
etc...,
},
如何打印(假设)FilesOnDisk和Files数组的id键。
我不知道如何到达那个嵌套数组。
答案 0 :(得分:0)
echo $json_output['project']['files'][0]['project-id'];
echo $json_output['project']['files'][0]['filenameOnDisk'];
echo $json_output['project']['files'][0]['version-id'];
或者你可以使用你想要的值数组将它放在foreach循环中(只要它们都在'files'数组中)。例如。
$wantedValues = array("project-id","filenameOnDisk","version-id");
foreach ($wantedValues as $value) {
echo $json_output['project']['files'][0][$value];
}
答案 1 :(得分:0)
我只需要在@SeeSamRun提供的代码中添加几行,以获得完整的"文件"阵列。
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