Question

我正在尝试编写一个程序，允许用户输入他们想要显示的多个随机等级以及生成列表的总和，平均值，最小值和最大值。等级范围从60到100。

程序正在正确打印min，并且总和将先前生成的总和与新生成的总和相加。如何更改它以便为最小值提供正确的输出，以便停止将新的前缀添加到新的？任何帮助将不胜感激。

输出的图像链接显示最小输出问题。最小应该是66.0，但它说59.0。 output import java.util.Scanner;

public class A03C
{
   public static void main(String[] args) 
   {
    Scanner input = new Scanner(System.in);

    System.out.print("How many scores? ");
    int howMany = input.nextInt();

    double score = 0;
    double sum = 0;
    double average = 0;
    double max = 0;
    double min = 60;

    while (howMany > 0)
    {
       for (int i = 1; i <= howMany; i++)
       {
        score = 60 + (int)(Math.random() * ((100 - 60) +1));

        if (letterGrade(score));

        sum += score++;

        average = (sum/howMany);

        if (score > max)
               max = score;

        if (score < max)
               min = score;

       }
       System.out.println("Sum: " + sum);
       System.out.println("Average: " + average);
       System.out.println("Max: " + (max - 1));
       System.out.println("Min: " + (min - 1));

       System.out.println("How many scores? ");
       howMany = input.nextInt();
    }

   }

    public static boolean letterGrade(double score)
    { 
       if (score >= 92.0) 
          System.out.println(score + " is an A");
       else if (score >= 83.0)
          System.out.println(score + " is a B"); 
       else if (score >= 75.0)
          System.out.println(score + " is a C");
       else 
          System.out.println(score + " is an F");
       return false;
    }   
}

Answer 1

执行后只需清理sum变量，我也将letterGrade的返回值更改为true：

import java.util.Scanner;

public class A03C {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);

        System.out.print("How many scores? ");
        int howMany = input.nextInt();

        double score = 0;
        double sum = 0;
        double average = 0;
        double max = 0;
        double min = 60;

        while (howMany > 0) {
            for (int i = 1; i <= howMany; i++) {
                score = 60 + (int) (Math.random() * ((100 - 60) + 1));

                if (letterGrade(score))
                    sum += score++;

                average = (sum / howMany);

                if (score > max)
                    max = score;

                if (score < max)
                    min = score;

            }
            System.out.println("Sum: " + sum);
            System.out.println("Average: " + average);
            System.out.println("Max: " + (max - 1));
            System.out.println("Min: " + (min - 1));

            System.out.println("How many scores? ");

            sum = 0;

            howMany = input.nextInt();
        }

    }

    public static boolean letterGrade(double score) {
        if (score >= 92.0)
            System.out.println(score + " is an A");
        else if (score >= 83.0)
            System.out.println(score + " is a B");
        else if (score >= 75.0)
            System.out.println(score + " is a C");
        else
            System.out.println(score + " is an F");
        return true;
    }
}

Answer 2

在继续之前，我绝对认为你应该阅读@joe C评论。据我了解你是初学者，我将解释我所做的改变。

import java.util.Scanner;


public class A03C
{
   public static void main(String[] args) 
   {
    Scanner input = new Scanner(System.in);

    System.out.print("How many scores? ");
    int howMany = = input.nextInt();

    double score = 0;
    double sum = 0;
    double average = 0;
    double max = 60;
    double min = 100;

    while (howMany > 0)
    {
       for (int i = 1; i <= howMany; i++)
       {
        score = 60 + (int)(Math.random() * ((100 - 60) +1));

        letterGrade(score);

        sum += score++;

        average = (sum/howMany);

        if (score > max)
               max = score;

        if (score < min)
               min = score;

       }
       System.out.println("Sum: " + sum);
       System.out.println("Average: " + average);
       System.out.println("Max: " + (max - 1));
       System.out.println("Min: " + (min - 1));

       System.out.println("How many scores? ");
       howMany = input.nextInt();
    }

   }

    public static void letterGrade(double score)
    { 
       if (score >= 92.0) 
          System.out.println(score + " is an A");
       else if (score >= 83.0)
          System.out.println(score + " is a B"); 
       else if (score >= 75.0)
          System.out.println(score + " is a C");
       else 
          System.out.println(score + " is an F");
    }   
}

从函数 letterGrade 开始。由于函数始终返回false并且只打印一个句子，因此可以将 boolean 替换为 void 。

你犯的另一个错误是，如果你想找到 max 和 min ，变量应该是你想要的倒数。因此变量max应采用最小变量（60）和最大值（100）。

最后，为了更改变量 max 和 min ，您必须将新值与其当前值进行比较。例如，要更改 min 值，您必须将得分与当前 min 进行比较。

希望它有所帮助。

如何从用户输入打印正确的最小值和最大值

2 个答案: