Question

我正在关注2017年秋季的Standford ios课程。当教授通过演示时，我会像他一样输入和运行。他展示了如何使用lazy与var允许使用UIButton计数进行变量初始化。当我添加lazy关键字时，错误不会消失。认为这可能是一个xcode更新相关的问题，我下载了其他人的项目版本，该项目没有问题。代码在下面，有什么想法吗？：/

类ViewController：UIViewController {

lazy var game = ConcentrationModel(numberOfPairsOfCards: (cardButtons.count + 1) / 2)


//Could have had var flipCount: Int = 0
//But it is inferred
var flipCount = 0 {
    didSet {
        flipCountLabel.text = "Flips: \(flipCount)"
    }
}

var emojiChoices = ["","","","","",""]

@IBOutlet var cardButtons: [UIButton]!


@IBOutlet weak var flipCountLabel: UILabel!

@IBAction func touchCard(_ sender: UIButton) {
    flipCount += 1
    if let cardNumber = cardButtons.index(of: sender) {
        flipCard(withEmoji: emojiChoices[cardNumber], on: sender)
        print("cardNumber = \(cardNumber)")
    } else {
        print("chosen card was not in cardButtons")
    }
    print("agh!!! a ghost")
}


func flipCard(withEmoji emoji: String, on button: UIButton) {
    if button.currentTitle == emoji {
        button.setTitle("", for: UIControlState.normal)
        button.backgroundColor = #colorLiteral(red: 1, green: 0.5763723254, blue: 0, alpha: 1)
    } else {
        button.setTitle(emoji, for: UIControlState.normal)
        button.backgroundColor = #colorLiteral(red: 0.9999960065, green: 1, blue: 1, alpha: 1)
    }
}

}

Answer 1

要初始化一个依赖于另一个属性值的惰性属性，必须使用闭包语法

lazy var game : ConcentrationModel = { 
     return ConcentrationModel(numberOfPairsOfCards: (self.cardButtons.count + 1) / 2) 
}()

在swift中使用lazy时遇到麻烦

1 个答案: