我有这两个模型:
class Model_user extends ORM { protected $_has_many = array('credits', array('model'=>'credit', 'foreign_key'=>'user')); } class Model_credit extends ORM { protected $_belongs_to = array('user', array('model'=>'user', 'foreign_key'=>'user')); protected $_tb = 'credits'; protected $_pk = 'id'; // method to be implemented public function total() { return $total_credits_available; } } // accessing the 'total' method $user = ORM::factory('user', 1); $total_credits = $user->credits->total();
关键是如何实现'total'方法,它的作用如下:
return DB::select(array(DB::expr('SUM(qty * sign)'), 'total')) ->from($this->_tb) ->where('user', '=', $user_id) ->execute() ->total;
该方法计算用户的学分(可以是+学分和-credits)并返回可用学分总数。只要我使用ORM :: factory方法创建用户对象,我就想以这样的方式实现'total'方法,它使用加载的资源而不是运行新的查询(我写了上面的查询来演示业务逻辑)。
有什么建议吗? :)
答案 0 :(得分:6)
<?php
class Model_user extends ORM {
protected static $_totals = array();
protected $_has_many = array('credits', array('model'=>'credit', 'foreign_key'=>'user'));
public function total()
{
$total = Arr::get(Model_User::$_totals, $this->id, FALSE);
if ($total !== FALSE)
return $total;
return Model_User::$_totals[$this->id] = $this->credits
->select(array(DB::expr('SUM(qty * sign)'), 'total'))
->find()
->total;
}
}