Question

我在尝试编译时遇到此错误。这曾经在我使用sdk 23时工作，但现在我已升级到26，我无法将其编译。

Error:(41, 13) error: cannot find symbol class SimpleAdapter

这是我的代码，它会从网站上获取联系人列表，并在列表视图中显示这些联系人。

public class ContactsActivity extends Activity {
private SimpleAdapter adpt;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_contacts);

    adpt  = new SimpleAdapter(new ArrayList<Contact>(), this);
    adpt.setStyle(R.layout.contact_list_item);
    ListView lView = (ListView) findViewById(R.id.listview_contacts);

联系人类如下所示，这是我将返回的xml转换回来的内容。

public class Contact implements Serializable {

private String Name;
private String Phone;
private String Cell;
private String Email;
private String Address;
private String Work;

public Contact() {
    super();
}
public Contact(String name, String phone, String cell, String email, String address,String work) {
    super();
    this.Name = name;
    this.Phone = phone;
    this.Cell = cell;
    this.Email = email;
    this.Address = address;
    this.Work = work;
}

public String getName() {
    return Name;
}

public void setName(String name) {
    this.Name = name;
}

public String getPhone() {
    return Phone;
}

public void setPhone(String phone) {
    this.Phone = phone;
}

public String getCell() {
    return Cell;
}

public void setCell(String cell) {
    this.Cell = cell;
}

public String getEmail() {
    return Email;
}

public void setEmail(String email) {
    this.Email = email;
}

public String getAddress() {
    return Address;
}

public void setAddress(String address) {
    this.Address = address;
}

public String getWork() {
    return Work;
}

public void setWork(String work) {
    this.Work = work;
}

}

请让我知道我哪里出错。

Answer 1

您需要创建一个SimpleAdapter，可以从ArrayAdapter，BaseAdapter扩展，...

Android简易适配器

1 个答案: