Question

我正在建立一个有游戏的网站。

游戏的目的是获取在网络上查找某些信息的要点当用户找到一个令牌，一条信息，进行检查并且他/她获得该检查的积分。

这是我到目前为止建立的数据库：

CREATE TABLE IF NOT EXISTS `user` (
  `userid` int(11) NOT NULL AUTO_INCREMENT,
  `points` int(11) NOT NULL,
  PRIMARY KEY (`userid`)
) ENGINE=MyISAM  DEFAULT AUTO_INCREMENT=1 ;


CREATE TABLE IF NOT EXISTS `checkings` (
  `checkingsid` int(11) NOT NULL AUTO_INCREMENT,
   `userid` int(11) NOT NULL,
  `tokensid` int(11) NOT NULL,  
   `checked` int(11) NOT NULL,
  PRIMARY KEY (`checkingsid`)
) ENGINE=MyISAM  DEFAULT AUTO_INCREMENT=1 ;


CREATE TABLE IF NOT EXISTS `tokens` (
  `tid` int(11) NOT NULL AUTO_INCREMENT,
  `tokensid` int(11) NOT NULL,
   `name` varchar(255) NOT NULL,
   `points` int(11) NOT NULL,
  PRIMARY KEY (`tid`)
) ENGINE=MyISAM  DEFAULT AUTO_INCREMENT=1 ;

这是我的代码。

它的问题是：我如何知道是否已经为该令牌提供了积分？请帮我逻辑，我已经失去了我的范围，我看不到这样做的方法。我可能开始编写错误的方向。我解释了我在代码中要做的事情。

非常感谢

<?php  
                //connected to database and obtained $userId and $tokenID already
              $query0 = "select * from checkings where userid=".$userId." and tokensid=".$tokenId."";
              $result0 = mysql_query($query0);
              $row0 = mysql_fetch_array($result0); 

               if (($row0['checked']!=' ')|| ($row0['checked']!='0')){ // if checked is empty or 0 the user didn't do the checking in this token yet

                  if (($row0['checked']==1)&&($row0['userid']==$userId)&&($row0['tokensid']==$tokenId) ){//the checking has already been inserted

                      //how many points are given for checking in this token? 
                      $query2 = "select points from tokens where tokensid='".$tokenId."'";
                      $result2 = mysql_query($query2);  
                      $row2 = mysql_fetch_array($result2);
                      $pointstoken = $row2['points']; 

                       //How many points have the user? 
                      $query3 = "select points from user where userid='".$userId."'";
                      $result3 = mysql_query($query3);  
                      $row3 = mysql_fetch_array($result3);
                      $pointsUser = $row3['points'];  

                      //user points are updated after checking in this token 
                      $pointsTotal = $pointsUser+$pointstoken;  
                      $query4 = "update user set points=".$pointsTotal." where userid=".$userId." ";
                      $result4 = mysql_query($query4);  



                    }else{//here I do the checking in the token inseting the ids plus a 1 as for checked 
                      $query1 = "insert into checkings (userid, tokensid,checked ) values (".$userId.",".$tokenId.",1)";
                      $result1 = mysql_query($query1);


                  }   

               }else{ echo "Hi, user ".$userId." you've already done the checking in token id ".$tokenId." ";}
     ?>

Answer 1

检查表是否存储了用户找到的检查？

在这种情况下，在授予用户任何积分之前先搜索该表。

如果没有，请为用户+检查/令牌创建一个表，跟踪用户找到并获得的每个项目，并在每次用户提交查找时搜索该表。

网络检查游戏，帮助它的逻辑

1 个答案: