Question

如果我从第三方导入模块，但是他们使用的语法与我的不一致，那么pep8是否有好的方法呢？

示例：我需要使用无法编辑的第三方模块，并且它们的命名约定不是很好。

示例：

thisIsABase_function(self,a,b)

我有一些代码将pep8命名为pep8，但我想知道如何通过新的pep8名称访问这些函数？

def _pep8ify(name):
    """PEP8ify name"""
    import re
    if '.' in name:
        name = name[name.rfind('.') + 1:]
    if name[0].isdigit():
        name = "level_" + name
    name = name.replace(".", "_")
    if '_' in name:
        return name.lower()
    s1 = re.sub('(.)([A-Z][a-z]+)', r'\1_\2', name)
    return re.sub('([a-z0-9])([A-Z])', r'\1_\2', s1).lower()

我有没有办法在导入时PEP8这些名字？

Answer 1

您可以使用上下文管理器自动对来自导入模块的符号进行pep8ify，如：

实施例

with Pep8Importer():
    import funky

代码：

class Pep8Importer(object):

    @staticmethod
    def _pep8ify(name):
        """PEP8ify name"""
        import re
        s1 = re.sub('(.)([A-Z][a-z]+)', r'\1_\2', name)
        return re.sub('([a-z0-9])([A-Z])', r'\1_\2', s1).lower()

    def __enter__(self):
        # get list of current modules in namespace
        self.orig_names = set(dir(sys.modules[__name__]))

    def __exit__(self, exc_type, exc_val, exc_tb):
        """ Pep8ify names in any new modules

        Diff list of current module names in namespace.
        pep8ify names at the first level in those modules
        Ignore any other new names under the assumption that they
        were imported/created with the name as desired.
        """
        if exc_type is not None:
            return
        new_names = set(dir(sys.modules[__name__])) - self.orig_names
        for module_name in (n for n in new_names if not n.startswith('_')):
            module = sys.modules[module_name]
            for name in dir(module):
                pep8ified = self._pep8ify(name)
                if pep8ified != name and not name.startswith('_'):
                    setattr(module, pep8ified, getattr(module, name))
                    print("In mModule: {}, added '{}' from '{}'".format(
                        module_name, pep8ified, name))

测试代码：

with Pep8Importer():
    import funky

print(funky.thisIsABase_function)
print(funky.this_is_a_base_function)

funky.py

thisIsABase_function = 1

结果：

In module: funky, added 'this_is_a_base_function' from 'thisIsABase_function'

1
1

Answer 2

我觉得这样的事情符合你的要求：

# somemodule.py
def func_a():
    print('hello a')

def func_b():
    print('hello b')


# yourcode.py
import inspect
import importlib

def pepimports(the_module_name):
    mymodule = importlib.import_module(the_module_name)
    myfuncs = inspect.getmembers(f, inspect.isfunction)
    for f in myfuncs:
        setattr(mymodule, _pep8ify(f[1].__name__) , f[1])
    return mymodule

mymodule = pepimports('some_module_name')
# you can now call the functions from mymodule
# (the original names still exist, so watch out for clashes)
mymodule.pepified_function()

它有点像hackish，但我已经尝试过了（python 3.5）并且似乎有效（至少在一个简单的例子中）。

如何导入PEP8包

2 个答案:

实施例

代码：

测试代码：

funky.py

结果：