size = (raw_input ('\nWhat Size do you want?').lower()
l_size =['large' , 'lerge' , 'l', 'larg' ,'lorge' ,]
m_size =['m' , 'med' , 'medium']
s_size =['s' , 'small' , 'smell', 'smoll']
如果用户输入不正确,我正在使用它来获取正确的输入
while size not in ('l_size', 'm_size','s_size'):
print ("\033[1;31m Invalid input! Trying Again\n"),
size = raw_input("\033[1;32;40m What Size do you want? \n")
如果用户输入错误,我想从头开始运行程序
if size in l_size:
print '\nYour coffee is Large! '
elif size in m_size:
print '\n Your Coffee is Medium'
elif size in s_size:
print '\nYour Coffee is Small'
else:
print '\nIncorrect Typing! Type Properly'\
答案 0 :(得分:0)
您想要列表连接:
while size not in l_size + m_size + s_size:
答案 1 :(得分:0)
删除raw_input()
附近的额外括号。
size = raw_input('\nWhat Size do you want?').lower()
l_size = ['large', 'lerge', 'l', 'larg','lorge']
m_size = ['m', 'med', 'medium']
s_size = ['s', 'small', 'smell', 'smoll']
虽然size
不在这些列表中,但您需要重置size
,而不是创建新变量num
。就像@iBug所说,你需要连接列表来循环。
while size not in l_size + m_size + s_size:
print("\033[1;31m Invalid input! Trying Again\n")
size = raw_input("\033[1;32;40m What Size do you want? \n")
答案 2 :(得分:0)
size = raw_input("\033[1;32;40m What Size do you want? \n").lower()
l_size = ['large', 'lerge', 'l', 'larg','lorge']
m_size = ['m', 'med', 'medium']
s_size = ['s', 'small', 'smell', 'smoll']
while size not in l_size + m_size + s_size:
print ("\033[1;31m Invalid input! Trying Again\n"),
size = raw_input("\033[1;32;40m What Size do you want? \n").lower()
l_size = ['large', 'lerge', 'l', 'larg','lorge']
m_size = ['m', 'med', 'medium']
s_size = ['s', 'small', 'smell', 'smoll']
if size in l_size:
print '\n Your coffee is Large! '
elif size in m_size:
print '\n Your Coffee is Medium'
elif size in s_size:
print '\n Your Coffee is Small'
else:
print '\n Incorrect Typing! Type Properly'\