Question

我有一个MS Access应用程序，在表单上有一个按钮，应该移动文件，更新记录的字段并打开包含以下参数的网页： 1）访问记录的ID 2）更新字段的值3）密码字。

除了打开网页外，一切正常。

我发布了这篇文章：How to open a URL from MS Access with parameters并撰写了一行CreateObject（＆＃34; Shell.Application＆＃34;）......

            FSO.MoveFolder FLD_READY & "\" & rs.Fields(order_int_ID), FLD_SERVER & "\" & rs.Fields(order_int_ID)
            rs.Edit: rs.Fields(order_stage) = os07: rs.Update
            CountFile = CountFile + 1
            CreateObject("Shell.Application").Open "https://example.com/status/" & "/" & rs.Fields(order_int_ID) & "/" & 'os07' & "/" & 'secretword'

请告诉你 - 它有什么问题？我应该如何更改它以使其正常工作？

这是整个脚本。提到的块几乎就在最后。

' Order_stage status
Private Const os06 = "06"
Private Const os07 = "07"

' Transfer to server
Private Const FTP_TRANSFER_TYPE_UNKNOWN     As Long = 0
Private Const INTERNET_FLAG_RELOAD          As Long = &H80000000
Private Const FORMAT_MESSAGE_FROM_HMODULE = &H800
Private szErrorMessage As String
Private Const INTERNET_OPEN_TYPE_PRECONFIG = 0
Private Const FTP_TRANSFER_TYPE_ASCII = &H1
Private dwType As Long
Private Const FtpConnectionFile = "D:\ftp_connection.txt"
Private Const FTP_UP_HOME = "public_html/"


'Folders
Private Const FLD_READY = "d:\10-5-0-Ready"
Private Const FLD_SERVER = "d:\10-6-0-Server"



Private Sub Ctl10_50___SERVER_Click()

  Dim ftpHost As String
  Dim ftpPort As Long
  Dim ftpUser As String
  Dim ftpPassword As String

  Dim CountFile As Integer
  Dim hOpen   As Long
  Dim hConn   As Long
  Dim hPut    As Long

  Dim ftpCurrentDirectory As String
  Dim szDir As String

  Dim strTextLine As String
  Dim FSO As Object
  Set FSO = CreateObject("Scripting.FileSystemObject")

  Dim oFolder As Object
  Dim oSubFolder As Object
  Dim oFile As Object
  Dim strFileExt As String
  Dim Strt As Integer

  Dim i As Integer: i = 0

  Dim iFile As Integer: iFile = FreeFile
  Open FtpConnectionFile For Input As #iFile
  Do Until EOF(1)
    Line Input #1, strTextLine
    Select Case i
     Case Is = 0:               ftpHost = Trim(strTextLine)
     Case Is = 1:               ftpPort = CLng(Trim(strTextLine))
     Case Is = 2:               ftpUser = Trim(strTextLine)
     Case Is = 3:               ftpPassword = Trim(strTextLine)
     Case Is = 4:               Exit Do
    End Select
    i = i + 1
  Loop
  Close #iFile

  hOpen = InternetOpenA("FTP Client", INTERNET_OPEN_TYPE_PRECONFIG, vbNullString, vbNullString, 0)
  If hOpen = 0 Then
        ErrorOut Err.LastDllError, "InternetOpen"
  End If

  dwType = FTP_TRANSFER_TYPE_ASCII

  hConn = InternetConnectA(hOpen, ftpHost, ftpPort, ftpUser, ftpPassword, 1, 0, 0)
  If hConn = 0 Then
        ErrorOut Err.LastDllError, "InternetConnect"
  End If

  If (FtpCreateDirectory(hConn, FTP_UP_HOME) = False) Then
        ErrorOut Err.LastDllError, "FtpCreateDirectory"
  Else
  End If

  If (FtpSetCurrentDirectory(hConn, FTP_UP_HOME) = False) Then
        ErrorOut Err.LastDllError, "FtpCreateDirectory"
  Else
  End If

   For Each oFolder In FSO.GetFolder(FLD_CHECK).SubFolders
     For Each oFile In oFolder.Files

        strFileExt = FSO.GetExtensionName(oFile)
       'MsgBox (strFileExt)
       If strFileExt = "psd2" Then
         Dim rs2 As Recordset
         Set rs2 = CurrentDb.OpenRecordset("SELECT A_INCOMING_ORDERS.order_int_ID, A_INCOMING_ORDERS.order_stage FROM A_INCOMING_ORDERS WHERE (A_INCOMING_ORDERS.order_int_ID = '" & oFolder.Name & "')")

         Do While Not rs2.EOF
            rs2.Edit: rs2.Fields(order_stage) = os40: rs2.Update
         rs2.MoveNext
         Loop
         rs2.Close
          FSO.MoveFolder oFolder.Path, FLD_ALTER & "\" & oFolder.Name

        End If

      Next
Next

  Dim rs As Recordset
  Set rs = CurrentDb.OpenRecordset("SELECT A_INCOMING_ORDERS.order_int_ID, A_INCOMING_ORDERS.order_stage FROM A_INCOMING_ORDERS WHERE (A_INCOMING_ORDERS.order_stage = '" & os06 & "');")
  CountFile = 0
  Do While Not rs.EOF

     If (FSO.FolderExists(FLD_READY & "/" & rs.Fields(order_int_ID))) Then
            If (FtpCreateDirectory(hConn, rs.Fields(order_int_ID)) = False) Then
               ErrorOut Err.LastDllError, "FtpCreateDirectory"
            Else
            End If

            For Each oFile In FSO.GetFolder(FLD_READY & "/" & rs.Fields(order_int_ID)).Files
               hPut = FtpPutFileA(hConn, FLD_READY & "/" & rs.Fields(order_int_ID) & "/" & oFile.Name, "/" & FTP_UP_HOME & "/" & rs.Fields(order_int_ID) & "/" & oFile.Name, 2, 0)
               If hPut = 0 Then
                  ErrorOut Err.LastDllError, "FtpPutFileA"
               Else
               End If
            Next
            FSO.MoveFolder FLD_READY & "\" & rs.Fields(order_int_ID), FLD_SERVER & "\" & rs.Fields(order_int_ID)
            rs.Edit: rs.Fields(order_stage) = os07: rs.Update
            CountFile = CountFile + 1
     CreateObject("Shell.Application").Open "https://example.com/status/" & "/" & rs.Fields(order_int_ID) & "/" & 'os07' & "/" & 'secretword'

     End If


  rs.MoveNext
  Loop
  rs.Close

  InternetCloseHandle hConn
  InternetCloseHandle hOpen
  MsgBox "Count: " & CountFile
End Sub

Answer 1

通过将文字文本与变量和常量连接来构造字符串：

CreateObject("Shell.Application").Open "https://example.com/status/%7" & rs.Fields(order_int_ID) & "%7D/%7B" & os07 & "%7D/secretword"

我没有看到名为secretword的声明变量或常量，因此不是 secretword 键入您的实际密码字。

以上构建基于您已删除的评论中的示例。该示例不在问题中，因此如果不需要任何文字字符，则删除它们。

Answer 2

这个问题的答案是：

Application.FollowHyperlink "https://example.com/status/" & rs.Fields(order_int_ID) & "/" & "os07" & "/" & "secretword", , True

此解决方案适合我。

如何在MS Access vba脚本中使用参数生成URL？

2 个答案: