Question

我阅读了所有类似主题的文章，但我找不到适合我的解决方案。我正在学习C＃，我用数组编写了简单的代码（猜测数字从1到100）。当用户点击正确的号码时，应用程序会按用户显示所有插入的号码。这些天我正在学习列表。我想编写类似的代码，但是使用List，限制尝试为10并显示所有插入的数字。无法弄清楚如何用List记住所有插入的数字。我在几个地方找到了命令 out ，但有没有简单的方法来做到这一点。如果我理解列表比数组更实用。我不需要确定用户可以尝试多少次尝试... 显然，编写InsertedNumber.Add（c）是不够的代码简单而简短，我想我可以复制所有代码。提前谢谢。

    static void Main(string[] args)
        {
            Random rnd = new Random();
            int b = rnd.Next(1, 100);
            Console.WriteLine(b);
            int c;
            int NumberOfTries = 1;

            Console.WriteLine("Guess number from 1 to 100. You have 10 tries.");
            for (int i = 0; i <= 10; i++)
            {
                if (i == 10) { Console.WriteLine("\nYou tried 10 times. Game is 
 over!"); break; }
                Console.Write("\nGuess number: ");
                List<int> InsertedNumbers = new List<int>();
                c = Convert.ToInt32(Console.ReadLine());
                InsertedNumbers.Add(c);
                    if (c == b)
                    {
                        Console.WriteLine("Bravo. You had {0} tries.", NumberOfTries);
                        foreach (var item in InsertedNumbers)
                        {
                            Console.WriteLine(item);
                        }
                        for (int j = 0; j < InsertedNumbers.Count; j++)
                        {
                            Console.WriteLine("{0}", InsertedNumbers[j]);
                        }
                         break;
                    }
                    else if (c < b)
                    {
                        Console.WriteLine("No. My number is larger then " + c);
                        NumberOfTries++;
                    }
                    else if (c > b)
                    {
                        Console.WriteLine("No. My number is smaller then " + c);
                        NumberOfTries++;
                    }
            } 
            Console.ReadLine();

Answer 1

如果我正确理解您的问题，您打印的问号列表无效。

这是因为您在循环的每次迭代中都创建了一个新的List。所以一切正常。但是每次迭代都会创建一个新的List，覆盖上一次迭代中的那个。所以只需在开始迭代之前创建一次List，一切都应该没问题。

    private static void Main(string[] args)
    {
        List<int> InsertedNumbers = new List<int>(); //Create List before the loop
        Random rnd = new Random();
        int b = rnd.Next(1, 100);
        Console.WriteLine(b);
        int c;
        int NumberOfTries = 1;

        Console.WriteLine("Guess number from 1 to 100. You have 10 tries.");
        for (int i = 0; i <= 10; i++)
        {
            if (i == 10)
            {
                Console.WriteLine("\nYou tried 10 times. Game is over!");
                break;
            }

            Console.Write("\nGuess number: ");
            c = Convert.ToInt32(Console.ReadLine());
            InsertedNumbers.Add(c);

            if (c == b)
            {
                Console.WriteLine("Bravo. You had {0} tries.", NumberOfTries);
                foreach (int item in InsertedNumbers)
                {
                    Console.WriteLine(item);
                }
                for (int j = 0; j < InsertedNumbers.Count; j++)
                {
                    Console.WriteLine("{0}", InsertedNumbers[j]);
                }
                break;
            }
            else if (c < b)
            {
                Console.WriteLine("No. My number is larger then " + c);
                NumberOfTries++;
            }
            else if (c > b)
            {
                Console.WriteLine("No. My number is smaller then " + c);
                NumberOfTries++;
            }
        }
        Console.ReadLine();
    }

Answer 2

首先：提取方法，不要将所有内容塞入单个Main。当InsertedNumbers是PlayGame的本地变量时，它更容易维护。如果您要打印所有InsertedNumbers项，可以尝试使用String.Join方法

   private static int GuessNumber() {
     Console.Write("\nGuess number: ");

     int result = 0; 

     // Check User Input: what if the inserted value is "bla-bla-bla"? 
     while (!int.TryParse(Console.ReadLine(), out result))         
       Console.WriteLine("Incorrect format; please, put an integer value");

     return result; 
   }

   private static void PlayGame(int value, int maxTries = 10) {
     List<int> InsertedNumbers = new List<int>();

     while (InsertedNumbers.Count < maxTries) {
       int guess = GuessNumber();

       InsertedNumbers.Add(guess);

       if (guess < value)
         Console.WriteLine($"No. My number is larger then {guess}"); 
       else if (guess > value)
         Console.WriteLine($"No. My number is smaller then {guess}");
       else {
         Console.WriteLine($"Bravo. You had {InsertedNumbers.Count} tries.");
         // Combine all items in InsertedNumbers into single string
         Console.WriteLine(string.Join(Environment.NewLine, InsertedNumbers));

         return;
       }
     }

     Console.WriteLine("\nYou tried maxTries times. Game is  over!");
   }

最后

  static void Main(string[] args) {
    Random rnd = new Random();

    PlayGame(rnd.Next(1, 100), 10); 
  }

如何用户用列表显示所有插入的整数？

2 个答案: