Question

CREATE TABLE #HR_XML (ID INT IDENTITY, Salaries XML)
GO
INSERT #HR_XML VALUES(
'<Salaries>
  <Marketing>
    <Employee>
      <Salary>42000</Salary>
      <Incentive>12000</Incentive>
      <LeaveEncashment>12000</LeaveEncashment>
    </Employee>
  </Marketing>
</Salaries>
')

Select * from #HR_XML

Declare @Node Varchar(100) = ''
SET @Node = 'LeaveEncashment'

UPDATE #HR_XML
SET Salaries.modify('replace value of 
(/Salaries/Marketing/Employee/[@Node]/text())[1] with ("60000")')
GO

 Select * from #HR_XML

Drop Table #HR_XML

从上面的sql查询，如何动态更新/传递@node

Answer 1

您应该使用Dynamic sql

 CREATE TABLE #HR_XML (ID INT IDENTITY, Salaries XML)
    GO
    INSERT #HR_XML VALUES(
    '<Salaries>
      <Marketing>
        <Employee>
          <Salary>42000</Salary>
          <Incentive>12000</Incentive>
          <LeaveEncashment>12000</LeaveEncashment>
        </Employee>
      </Marketing>
    </Salaries>
    ')

Select * from #HR_XML


    Declare @Node Varchar(100) = ''
    SET @Node = 'LeaveEncashment'

declare @sql varchar(max)
Set @sql  = '    UPDATE #HR_XML
    SET Salaries.modify(''replace value of 
    (/Salaries/Marketing/Employee/'+@Node+'/text())[1] with ("60000")'')'

 exec (@sql)
    GO

   Select * from #HR_XML

   Drop Table #HR_XML

Sql server替换节点为动态的Update xml节点值的值

1 个答案: