如何使用jest和酶来测试componentwillunmount中的函数?

时间:2018-01-29 11:12:57

标签: reactjs unit-testing jestjs enzyme

我正在尝试使用jest和酶为反应中的容器编写单元测试。我的反应代码是这样的:

AgentForm.js

import {
        resetStatusMessage,
        formSetError,
        formResetError,
        createAgent,
        updateAgent
        } from "../../actions";    

componentWillMount = () => {
const {
  agents,
  match,
  push,
  resetStatusMessage,
  formResetError
  } = this.props;
    this.edit = false;
    this.isNewAvatar = false;
    this.agent = {};
    if (match.params.id) {
      this.edit = true;
      this.agent = getAgent(agents, match.params.id);
      if ("undefined" === typeof this.agent) {
       push("/agents");
      }
  }
  resetStatusMessage();
  formResetError();
 };

我的测试代码是这样的:

import React from "react";
import ReactDOM from "react-dom";
import { Provider } from "react-redux";
import configureStore from "../../store/configureStore";
import AgentForm from "./index";
import { mount } from "enzyme";

 it("should call resetStatusMessage when mounted", () => {
 let mockResetStatusMessage = jest.fn(),
 store = configureStore();
 const wrapper = mount(
 <Provider store={store}>
  <AgentForm resetStatusMessage={mockResetStatusMessage} />
 </Provider>
 );
 expect(wrapper).toBeDefined();
 expect(mockResetStatusMessage).toHaveBeenCalled();
 });

但测试失败并显示错误消息:

expect(jest.fn()).toHaveBeenCalled()
Expected mock function to have been called

我在这里缺少什么?

1 个答案:

答案 0 :(得分:3)

您渲染组件很浅,这意味着它无法访问安装和卸载生命周期。使用mount包装器而不是浅包装器

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