Question

这是没有group by的查询，它完全显示数据

SELECT 
    [b].[FullName]
  , STUFF(
       (SELECT 
            ','+CONVERT(VARCHAR(30), [t].[pdate], 120)
        FROM [DBTrans] [t]
        WHERE [t].[dbID] = [uk].[ID] FOR
        XML PATH('')), 1, 1, '') AS [ins_Dates]
  , [InvNo]
  , [AdCaption]
  , CONCAT([AdCM], 'x', [AdCOL]) AS [SIZE]
  , [NetAmt]
  , [RecievedAmount]
  , [NetAmt] - [RecievedAmount] AS [O_S]
FROM [DailyBooking] [uk]
INNER JOIN [DBTrans]
     ON [uk].[ID] = [DBTrans].[dbID]
INNER JOIN [Publication] [b]
     ON [uk].[AdPub] = [b].[ID]
WHERE [b].[FullName] LIKE '%a%';

当我尝试为某些目的进行分组时，它会在不同的更改中显示不同的错误

例如：

Msg 8120，Level 16，State 1，Line 2 专栏＆＃39; DailyBooking.ID＆＃39;在选择列表中无效，因为它不包含在聚合函数或GROUP BY子句中。

SELECT 
    [b].[FullName]
  , STUFF(
       (SELECT 
            ','+CONVERT(VARCHAR(30), [t].[pdate], 120)
        FROM [DBTrans] [t]
        WHERE [t].[dbID] = [uk].[ID] FOR
        XML PATH('')), 1, 1, '') AS [ins_Dates]
  , [InvNo]
  , [AdCaption]
  , CONCAT([AdCM], 'x', [AdCOL]) AS [SIZE]
  , [NetAmt]
  , [RecievedAmount]
  , [NetAmt] - [RecievedAmount] AS [O_S]
FROM [DailyBooking] [uk]
INNER JOIN [DBTrans]
     ON [uk].[ID] = [DBTrans].[dbID]
INNER JOIN [Publication] [b]
     ON [uk].[AdPub] = [b].[ID]
WHERE [b].[FullName] LIKE '%a%'
GROUP BY 
    [b].[FullName];

Answer 1

假设其他列在功能上依赖于分组列，最简单的答案是

一个。按其他列分组：

    Select r.*
FROM
(SELECT 
    [b].[FullName]
  , STUFF(
       (SELECT 
            ','+CONVERT(VARCHAR(30), [t].[pdate], 120)
        FROM [DBTrans] [t]
        WHERE [t].[dbID] = [uk].[ID] FOR
        XML PATH('')), 1, 1, '') AS [ins_Dates]
  , [InvNo]
  , [AdCaption]
  , CONCAT([AdCM], 'x', [AdCOL]) AS [SIZE]
  , [NetAmt]
  , [RecievedAmount]
  , [NetAmt] - [RecievedAmount] AS [O_S]
FROM [DailyBooking] [uk]
INNER JOIN [DBTrans]
     ON [uk].[ID] = [DBTrans].[dbID]
INNER JOIN [Publication] [b]
     ON [uk].[AdPub] = [b].[ID]
WHERE [b].[FullName] LIKE '%a%') r
GROUP BY 
    [r].[FullName],
    [r].ins_Dates,
    [r].InvNo,
    [r].AdCaption,
    [r].SIZE,
    [r].NetAmt,
    [r].RecievedAmount,
    [r].O_S

或

湾使用聚合函数，例如max：

SELECT 
        max([b].[FullName])
      , STUFF(
           (SELECT 
                ','+CONVERT(VARCHAR(30), [t].[pdate], 120)
            FROM [DBTrans] [t]
            WHERE [t].[dbID] = [uk].[ID] FOR
            XML PATH('')), 1, 1, '') AS [ins_Dates]
      , max([InvNo])
      , max([AdCaption])
      , CONCAT([AdCM], 'x', [AdCOL]) AS [SIZE]
      , max([NetAmt])
      , max([RecievedAmount])
      , [NetAmt] - [RecievedAmount] AS [O_S]
    FROM [DailyBooking] [uk]
    INNER JOIN [DBTrans]
         ON [uk].[ID] = [DBTrans].[dbID]
    INNER JOIN [Publication] [b]
         ON [uk].[AdPub] = [b].[ID]
    WHERE [b].[FullName] LIKE '%a%'

无法通过两个内部联接进行分组

1 个答案: