Question

我有一个字典，其中包含'0/RP0': ['NCS1K4-CNTLR']等条目。对于每个条目，我必须在值中添加另一个字符串。例如，追加'OPERATIONAL'会产生'0/RP0': ['NCS1K4-CNTLR','OPERATIONAL']。我需要为完整的字典执行此操作，并有一个要追加的值列表。

我下面有两个词典，

new_dict =
{'0/RP0': ['NCS1K4-CNTLR'], '0/PM1': ['NCS1K4-2KW-AC'], '0/PM0': ['NCS1K4-2KW-AC'], '0/FT2': ['NCS1K4-FAN'], '0/FT0': ['NCS1K4-FAN'], '0/FT1': ['NCS1K4-FAN']}

new_dict_1=   
{'0/RP0': ['OPERATIONAL'], '0/PM1': ['OPERATIONAL'], '0/PM0': ['FAILED'], '0/FT2': ['OPERATIONAL'], '0/FT0': ['OPERATIONAL'], '0/FT1': ['OPERATIONAL']}

我想要输出如下，

{'0/RP0': ['NCS1K4-CNTLR','OPERATIONAL'], '0/PM1': ['NCS1K4-2KW-AC','OPERATIONAL'], '0/PM0': ['NCS1K4-2KW-AC','OPERATIONAL'], '0/FT2': ['NCS1K4-FAN','OPERATIONAL'], '0/FT0': ['NCS1K4-FAN','FAILED'], '0/FT1': ['NCS1K4-FAN','OPERATIONAL']}

Answer 1

提起您的评论，您的第二本字典可以很容易地与第一本字典合并：

dict1 = {'0/RP0': ['NCS1K4-CNTLR'], '0/PM1': ['NCS1K4-2KW-AC'], '0/PM0': ['NCS1K4-2KW-AC'], '0/FT2': ['NCS1K4-FAN'], '0/FT0': ['NCS1K4-FAN'], '0/FT1': ['NCS1K4-FAN']}

dict2 = {'0/RP0': ['OPERATIONAL'], '0/PM1': ['OPERATIONAL'], '0/PM0': ['FAILED'], '0/FT2': ['OPERATIONAL'], '0/FT0': ['OPERATIONAL'], '0/FT1': ['OPERATIONAL']}

for k in dict1.keys():
    if k in dict2:
        dict1[k].append(dict2[k][0])

print(dict1)

给出：

{'0/RP0': ['NCS1K4-CNTLR', 'OPERATIONAL'], '0/PM1': ['NCS1K4-2KW-AC', 'OPERATIONAL'], '0/PM0': ['NCS1K4-2KW-AC', 'FAILED'], '0/FT2': ['NCS1K4-FAN', 'OPERATIONAL'], '0/FT0': ['NCS1K4-FAN', 'OPERATIONAL'], '0/FT1': ['NCS1K4-FAN', 'OPERATIONAL']}

请注意，dict2[k][0]会被追加，否则我们会追加一个不是字符串的列表。

Answer 2

如果你有两个词典，一个带有列表，另一个带有要附加的字符串，你可以使用python dict.keys函数。

dict_of_lists = {...}
dict_to_append ={...}
for key in dict_of_lists.keys():
    dict_of_lists[key].append(dict_of_keys[key])

如果第二个dict包含列表，您可能希望使用extent而不是append。

Answer 3

您可以使用zip()方法但是已经提到过：字典在Python中是无序的，所以在您需要的代码中可能还有更多内容变化

In [14]: my_dict = {'ak': ['av'], 'bk': ['bv']}

In [15]: my_list = ['a1v', 'b1v']

In [16]: for element in zip(my_dict, my_list):
    ...:     my_dict[element[0]].append(element[1])
    ...:     

In [17]: my_dict
Out[17]: {'ak': ['av', 'a1v'], 'bk': ['bv', 'b1v']}

不要误导结果，也可能是{'ak': ['av', 'b1v'], 'bk': ['bv', 'a1v']}

很可能你需要两个dicts并将它们压缩，而不是像：

In [18]: my_dict = {'ak': ['av'], 'bk': ['bv']}

In [19]: my_dict_2 = {'ak': ['a1v'], 'bk': ['b2v']}

In [20]: for element in zip(my_dict, my_dict_2):
    ...:     my_dict[element[0]].append(my_dict_2[element[1]][0])
    ...:     

In [21]: my_dict
Out[21]: {'ak': ['av', 'a1v'], 'bk': ['bv', 'b2v']}

Answer 4

字典理解可能比循环更有效。以下方法还通过dict.get语句替换了对密钥存在的检查，并使用dict1 = {'0/RP0': ['NCS1K4-CNTLR'], '0/PM1': ['NCS1K4-2KW-AC'], '0/PM0': ['NCS1K4-2KW-AC'], '0/FT2': ['NCS1K4-FAN'], '0/FT0': ['NCS1K4-FAN'], '0/FT1': ['NCS1K4-FAN']} dict2 = {'0/RP0': ['OPERATIONAL'], '0/PM1': ['OPERATIONAL'], '0/PM0': ['FAILED'], '0/FT2': ['OPERATIONAL'], '0/FT0': ['OPERATIONAL'], '0/FT1': ['OPERATIONAL']} dict1_new = {k: v + dict2.get(k, []) for k, v in dict1.items()} # {'0/FT0': ['NCS1K4-FAN', 'OPERATIONAL'], # '0/FT1': ['NCS1K4-FAN', 'OPERATIONAL'], # '0/FT2': ['NCS1K4-FAN', 'OPERATIONAL'], # '0/PM0': ['NCS1K4-2KW-AC', 'FAILED'], # '0/PM1': ['NCS1K4-2KW-AC', 'OPERATIONAL'], # '0/RP0': ['NCS1K4-CNTLR', 'OPERATIONAL']}默认值。

database1:
  datasource:
    repository-package: com.sample.database1.repositories1,com.sample.database1.repositories2
    entity-packages: com.sample.database1.entities1,com.sample.database1.entities2

如何追加字典中的列表？

4 个答案: