Question

以下是示例，请帮助使用等效的JavaScript代码

array A = [{id: 1, name:'cat'},{id:2, name:'dog'},{id:3, name:'tiger'}];

array B = [{name:'cat'},{name:'dog'}];

结果

expected = [{id: 1, name:'cat'},{id:2, name:'dog'}];

需要根据数组B中可用的名称过滤数组A

类似于('cat','dog')中名称的SQL。

尝试使用array.filter和indexOf !== -1

但没有得到预期的结果。

Answer 1

随着阵列变大，构建查找对象可能会更好，但使用Array.prototype.filter()和Array.prototype.some()的简单方法可能如下所示：

＆＃13;

const a = [{id: 1, name:'cat'}, {id:2, name:'dog'}, {id:3, name:'tiger'}];
const b = [{name:'cat'}, {name:'dog'}];

const result = a.filter(x => b.some(y => x.name === y.name));

console.log(result);

＆＃13;

Answer 2

   const a = [{id: 1, name:'cat'}, {id:2, name:'dog'}, {id:3,    name:'tiger'}];
 const b = [{name:'cat'}, {name:'dog'}];


                    

           
   var res = a.filter((per)=>b.find((x)=>per.name===x.name))
   
   console.log(res)

javascript如何根据另一个对象数组过滤对象数组

2 个答案: