使用片段

时间:2018-01-29 00:38:25

标签: android mysql json listview android-fragments

我正在尝试开发我的第一个应用程序,其中包含一个导航抽屉。我目前正在尝试从mysql数据库(在xampp上运行)读取数据并将其显示在ListView中。我已阅读了很多教程,但由于我的.java类正在扩展Fragment(由于NavigationDrawer),我无法找到可行的解决方案。经过几个小时的阅读和测试,我想出了以下内容(我知道这不是最高贵的方式,但无论如何......)。不幸的是,在模拟器中尝试时,应用程序会一直停止。在我看来,方法getData()必须有问题。任何人都知道为什么?非常感谢你的帮助! 干杯, keja

public class newsFragment extends Fragment{

    View myView;
    ListView lv;
    String address = "http://127.0.0.1/android/words.php";
    InputStream is = null;
    String line = null;
    String result = null;
    String[] data;
    JSONObject jo = null;
    @Nullable
    @Override
    public View onCreateView(LayoutInflater inflater, @Nullable ViewGroup container, Bundle savedInstanceState) {
        myView = inflater.inflate(R.layout.news_layout,container,false);

        lv = (ListView)myView.findViewById(R.id.lv);
        StrictMode.setThreadPolicy((new StrictMode.ThreadPolicy.Builder().permitNetwork().build()));

        getData();

        ArrayAdapter<String> adapter = new ArrayAdapter<String>(getActivity(),android.R.layout.simple_list_item_1,data);
        lv.setAdapter(adapter);

        return myView;
    }

    private void getData(){
        try {
            URL url = new URL(address);
            HttpURLConnection con = (HttpURLConnection) url.openConnection();
            con.setRequestMethod("GET");
            is = new BufferedInputStream(con.getInputStream());
        } catch (Exception e) {
            e.printStackTrace();
        }

        //READ IS CONTENT INTO A STRING
        try {
            BufferedReader br = new BufferedReader(new InputStreamReader(is));
            StringBuilder sb = new StringBuilder();
            while((line=br.readLine())!=null){
                sb.append(line).append(" \n");
            }
            is.close();
            result = sb.toString();
        } catch (Exception e) {
            e.printStackTrace();
        }

        //PARSE JSON DATA
        try{
            JSONArray ja = new JSONArray(result);
            data = new String[ja.length()];
            for(int i=0;i<ja.length();i++){
                jo=ja.getJSONObject(i);
                data[i]=jo.getString("name");
            }
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

2 个答案:

答案 0 :(得分:0)

try {
    JSONArray ja = new JSONArray(result);
    data = new String[ja.length()]; 
    for(int i=0;i<ja.length();i++){
        jo=ja.getJSONObject(i);
        data[i]=jo.getString("name");
   }
    //here u pass data to arrayadapter and load to list view..

} catch (Exception e) {
    e.printStackTrace();
}

答案 1 :(得分:0)

我找到了解决方案!问题是&#34;服务器&#34;地址。模拟器似乎不喜欢&#34; localhost&#34;或&#34; 127.0.0.1&#34;,所以我不得不将其更改为我的动态IP地址。 : - )