Question

我期待$ Flag_CreditTrend为1.但它等于0。有什么想法吗？

$Note = "test, up"
$CreditScoreTrend  = ($Note -split ',')[1].trim()
$Flag_CreditTrend = 0
$CreditScoreTrend 
if ($CredScoretrend -match 'up') {$Flag_CreditTrend = 1}
#if ($CredScoretrend -like 'up') {$Flag_CreditTrend = 1}
#if ($CredScoretrend -eq 'up') {$Flag_CreditTrend = 1}
$Flag_CreditTrend

Answer 1

看看你写的是什么：

$Note = "test, up"
$CreditScoreTrend  = ($Note -split ',')[1].trim()
$Flag_CreditTrend = 0
$CreditScoreTrend 
if ($CredScoretrend -match 'up') {$Flag_CreditTrend = 1}
#if ($CredScoretrend -like 'up') {$Flag_CreditTrend = 1}
#if ($CredScoretrend -eq 'up') {$Flag_CreditTrend = 1}
$Flag_CreditTrend

第5行if ($CredScoretrend -match 'up') {$Flag_CreditTrend = 1}使用变量$CredScoretrend而不是您想要的变量$CreditScoreTrend。由于此新变量未分配，因此不匹配＆＃39; up＆＃39;如你所料。这将返回false，因此永远不会将Flag_CreditTrend指定为1.因此，$Flag_CreditTrend将返回您在第3行分配的值0。

Answer 2

变量参考错误，请查看注释行

$Note = "test, up"
$CreditScoreTrend  = ($Note -split ',')[1].trim()
$Flag_CreditTrend = 0
$CreditScoreTrend 
if ($CreditScoreTrend -match 'up') {$Flag_CreditTrend = 1}#here CreditScoreTrend is to be used
#if ($CredScoretrend -like 'up') {$Flag_CreditTrend = 1}
#if ($CredScoretrend -eq 'up') {$Flag_CreditTrend = 1}
$Flag_CreditTrend

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