我的数据结构如下。基本上,我创建了一个“追随者”类别作为每个键的子项,其中一个键代表一个民意调查。如果我的应用程序的当前用户ID列在“关注者”类别中,我希望该节点与我的查询相关。否则,我希望它被忽略。
这种类型的查询是否可行?我从顶层开始,“民意调查”,然后我必须遍历每个子密钥,然后在该密钥内“跟随”子项:
Query query = FirebaseDatabase.getInstance()
.getReference()
.child("Polls");
答案 0 :(得分:1)
这种查询是可能的。
您只需要查看每个轮询对象,看看您关注的user_ID是否存在于关注者列表中。
另一个解决方案是让Followers节点根据user_ID将关注者链接到他们关注的民意调查。
这在这里有更详细的描述:
https://firebase.google.com/docs/database/android/structure-data#flatten_data_structures
如果将数据拆分为单独的路径(也称为非规范化),则可以根据需要在单独的调用中有效地下载数据。考虑这种扁平结构:
{
// Chats contains only meta info about each conversation
// stored under the chats's unique ID
"chats": {
"one": {
"title": "Historical Tech Pioneers",
"lastMessage": "ghopper: Relay malfunction found. Cause: moth.",
"timestamp": 1459361875666
},
"two": { ... },
"three": { ... }
},
// Conversation members are easily accessible
// and stored by chat conversation ID
"members": {
// we'll talk about indices like this below
"one": {
"ghopper": true,
"alovelace": true,
"eclarke": true
},
"two": { ... },
"three": { ... }
},
// Messages are separate from data we may want to iterate quickly
// but still easily paginated and queried, and organized by chat
// conversation ID
"messages": {
"one": {
"m1": {
"name": "eclarke",
"message": "The relay seems to be malfunctioning.",
"timestamp": 1459361875337
},
"m2": { ... },
"m3": { ... }
},
"two": { ... },
"three": { ... }
}
}