我有两个表时间表和主题,我需要来自主题表的id,subject_name,而不是在特定部分的时间表中使用。
我正在使用此查询
SELECT subject.id, subject.subject_name
FROM timetable
LEFT JOIN subject
ON timetable.subject_id != subject.id AND timetable.class_id = subject.class_id
WHERE timetable.class_id = 1 and timetable.section_id =1
答案 0 :(得分:1)
我仍然认为这是一个重复的问题。虽然你的问题有点复杂。所以试试这个:
SELECT subject.id, subject.subject_name
FROM subject
LEFT JOIN timetable
ON timetable.subject_id = subject.id
AND timetable.class_id = subject.class_id
AND timetable.section_id = 1
WHERE subject.class_id = 1
AND timetable.id IS NULL
答案 1 :(得分:0)
这个简单的查询有效。
SELECT id, subject_name FROM subject WHERE class_id = 1
AND id NOT IN (SELECT subject_id from timetable where section_id=1)