Question

我尝试在将表单结果保存到CSV文件之前从表单结果中更改/删除/替换它。

基本过程：

用户填写的表格。提交
结果写入CSV文件（打开，写入，关闭）
发送电子邮件至电子邮件地址。（邮件：主题，主题，信息，标题）

我已尝试使用“\”包装数据，如此处所述＆gt;＆gt; Write to .csv file with PHP (Commas in Data Error)

这是我的基本形式＆gt; form.php的

<form action="thanks.php" method="post" >
    <label for="Title">Title</label>
    <select name="Title" class="form-control">
        <option value=""> - select - </option>
        <option value="Mr.">Mr.</option>
        <option value="Mrs.">Mrs.</option>
    </select>

    <label for="FirstName">First Name *</label>
    <input name="FirstName" type="text" value="" id="FirstName">

    <label for="LastName"> Last Name *</label>
    <input name="LastName" type="text" value="" id="LastName">

    <label for="Email">Email Address *</label>
    <input name="Email" type="text" value="" id="Email">

    <label for="Comments">Comments</label>
    <textarea name="Comments" rows="2" class="form-control" id="Comments"></textarea>

    <label for="Description">Description</label>
    <textarea name="Description" rows="2" class="form-control" id="Description"></textarea>

    <button type="submit">Submit</button>
</form>

我的工作是什么：

将填好的表格数据收集到thanks.php
打开并写入csv文件（两次 - 备份）
将表单数据作为html发送到电子邮件

thanks.php

    <?php extract ($_POST); ?>
    <?php
        $Title =        $_POST['Title'];
        $FirstName =    $_POST['FirstName'];
        $LastName =     $_POST['LastName'];
        $Email =        $_POST['Email'];
        $Description =  $_POST['Description'];
        $Comments =     $_POST['Comments'];

        $fp = fopen("thedata.csv", "a");
        $savestring =
            $arr[] = "\"".$Title."\",".
            $arr[] = "\"".$FirstName."\",".
            $arr[] = "\"".$LastName."\",".
            $arr[] = "\"".$Email."\",".
            $arr[] = "\"".$Description."\",".
            $arr[] = "\"".$Comments."\"".
            "\n";
        fwrite($fp, $savestring);
        fclose($fp);

        $fp = fopen("backupdata.csv", "a");
        $savestring =
            $arr[] = "\"".$Title."\",".
            $arr[] = "\"".$FirstName."\",".
            $arr[] = "\"".$LastName."\",".
            $arr[] = "\"".$Email."\",".
            $arr[] = "\"".$Description."\",".
            $arr[] = "\"".$Comments."\"".
            "\n";
        fwrite($fp, $savestring);
        fclose($fp);
    ?> 

    <?php
    {
      PRINT "<h1>Thanks for filling out the form</h1>";
    }
    $to  = "email@address.com".",";
    $subject = "Contact the client";
    $message = "
      <html><head><style>body,p,td{font-family:calibri; font-size:11pt; color: #000000}</style></head><body>
        <table cellpadding=5>
          <tr>
            <td>Title</td>
            <td>FirstName</td>
            <td>LastName</td>
            <td>Email</td>
            <td>Description</td>
            <td>Comments</td>
          </tr>
          <tr>
            <td>$Title</td>
            <td>$FirstName</td>
            <td>$LastName</td>
            <td>$Email</td>
            <td>$Description</td>
            <td>$Comments</td>
          </tr>
        </table>
         </body>
      </html>
    ";
    $headers  = "MIME-Version: 1.0" . "\r\n";
    $headers .= "Content-type: text/html; charset=iso-8859-1" . "\r\n";
    $headers .= "From:email@address.com" . "\r\n"; 
    mail($to, $subject, $message, $headers);
    ?>

什么不起作用......

当我打开csv文件（在excel / sheets中）时，我注意到人们正在为描述和/或注释字段添加逗号......所以自动添加了多列。

我尝试在$ savestring中使用分号但是它甚至没有分成列。只有一行，我在描述中放了一个逗号，就在下一列的位置。

所以我知道我需要在写入CSV之前用连字符（或其他东西）替换逗号THEY，以便不创建列，从而将数据格式化为额外的列。

我无法弄清楚如何：|

PHP - 将结果表单转换为CSV - 在写入之前替换逗号

0 个答案: