Question

我们说我有一个字符串：

"but i [C#min] do [G#min] believe there's"

如何将该字符串转换为：

"but i  do  believe there's" (basically removing everything in-between '[' and ']')

我希望[C#min]＆amp; [G#min]存储在另一个数组中。

Answer 1

＆＃13;

    var a = "but i [C#min] do [G#min] believe there's";
    console.log(a.replace(/\[(.[^\[\]]*)\]/g, '')); // "but i  do  believe there's"
    console.log(a.match(/\[(.[^\[\]]*)\]/g)); // ["[C#min]", "[G#min]"]

＆＃13;

RegExp与[，]之间的所有内容相匹配，但[，]除外。

您可能需要删除替换周围留下的额外空白区域。

Answer 2

您可以使用正则表达式：

＆＃13;

    var text = "but i [C#min] do [G#min] believe there's";
    var regexp = /(\[[^\]]*\])/g;

    var matches = text.match(regexp);
    text = text.replace(regexp, '').replace(/  /g, ' ');
    console.log(text);

＆＃13;

matches将包含数组["[C#min]", "[G#min]"]。

注意：文本的第二个replace处理错误保留的双重空格。

Answer 3

尝试这种直截了当的方式：

    var str = "but i [C#min] do [G#min] believe there's";
    
    var start, stop, newStr = '', removed = '', counter =1;
    while(str.search(/\[.*\]/g) > 0) {
      start = str.indexOf('[');
      stop = str.indexOf(']');
      newStr += str.substring(0, start);
      removed += str.substring(start, stop+1);
      str =  str.substring(stop+1, str.length);
      counter++;
      if(counter > 3) break;
    }
    newStr += str;
    
    console.log(newStr);

Answer 4

没有正则表达式，简单方法：

＆＃13;

    var string = "but i [C#min] do [G#min] believe there's";
    array = []; 
    filteredString = ""
    
    for (i=0;i<string.length;i++){
        
        if (string[i] != '[') {
            filteredString += string[i];
            continue;
        }
        newstring = ""+string[i];
        do {
                newstring += string[++i]; 
            
        } while (string[i]!=']');
        array.push(newstring);
    }

console.log(array);
console.log(filteredString);

＆＃13;

Answer 5

您可以使用正则表达式查找括号中的字符串，然后使用String.replace()将其删除。剥离的部分将在一个数组中，用于您需要的任何用途。

var input = "but i [C#min] do [G#min] believe there's";
var reg = /\[(.*?)\]/g;           // Patthen to find
var matches = input.match(reg);   // Find matches and populate array with them
var output = input.replace(reg, "").replace(/\s\s/g, " ");  // Strip out the matches and fix spacing
console.log(matches); // Just for testing
console.log(output);  // Result

Answer 6

您可以按[：

分割字符串

function parseString(input) {
    output = {
        values: [],
        result: ""
    };
    input = input.split('[');
    for (var index = 0; index < input.length; index++) {
        var closingPosition = input[index].indexOf("]");
        if ((index > 0) && (closingPosition + 1)) {
            output.values.push('[' + input[index].substring(0, closingPosition) + ']');
            if (input[index].length > closingPosition) {
                output.result += input[index].substring(closingPosition + 1);
            }
        } else {
            output.result += input[index];
        }
    }
    return output;
}

如何删除指定字符之间的字符串并存储删除的字符串（Javascript）

6 个答案: