我的项目是使用Spring Boot和Kotlin构建的。
我有一个可能有父消息的类Message
(在响应消息时),代码如下所示:
@Entity
class Message(
@field: Id
@field:GeneratedValue var id : Long = 0,
@field: ManyToOne(targetEntity = Employee::class)
var sender:Employee?=null,
@field: ManyToOne(targetEntity = Employee::class)
var receiver:Employee?=null,
var time:LocalDateTime,
var content: String,
var read:Boolean,
@field: ManyToOne(targetEntity = Message::class)
@Nullable
var father:Message?=null)
{}
调用此查询时(使用JpaRepository):
fun findByReceiverIdAndReadFalse(id:Long):List<Message>
我收到此错误:
Unknown column 'message0_.father_id' in 'field list'
实际应该是message0_.father.id
,而不是father_id
(父亲是消息实体)。
Hibernate构建的完整查询是:
select
message0_.id as id1_5_,
message0_.content as content2_5_,
message0_.father_id as father_i5_5_,
message0_.read as read3_5_,
message0_.receiver_id as receiver6_5_,
message0_.sender_id as sender_i7_5_,
message0_.time as time4_5_
from
message message0_
left outer join
employee employee1_
on message0_.receiver_id=employee1_.id
where
employee1_.id=?
and message0_.read=0
Employee
上课:
@Entity
data class Employee(
@field: Id
@field:GeneratedValue var id : Long = 0,
var username : String = "",
var password : String ="",
var name : String ="",
var lastName: String ="",
var phone : String="",
var email : String ="",
var sex : String ="",
var active : Boolean = false,
@field: ManyToOne(targetEntity = District::class)
var district : District? = null,
@field: ManyToOne(targetEntity = Company::class)
var company : Company? = null,
var picture:String="",
var resetPasswordCode:String="",
// código que se le envía al usuario en el momento que crea
// la cuenta, deberá abrir en enlace del correo para activarla
// de ahí que "active" sea false.
var activationCode : String="",
// La fecha en que caduca el código activación: 5 días para activar
var activationCodeExpiration : LocalDateTime = LocalDateTime.now().plusDays(5),
var enabled : Boolean = true,
var accountNonExpired: Boolean = true,
var credentialsNonExpired: Boolean = true,
var accountNonLocked : Boolean = true,
@field: OneToMany(targetEntity = Roles::class) var roles :MutableSet<Roles> = mutableSetOf())
{
fun toUser() : User
{
val authorities = mutableSetOf<GrantedAuthority>()
roles.forEach{authorities.add(SimpleGrantedAuthority(it.role))}
return
User(username,password,enabled,accountNonExpired,credentialsNonExpired,accountNonLocked, authorities)
}
}
有没有办法强制使用正确的字段? 我错过了什么吗?
答案 0 :(得分:1)
问题是字段>>> name = ['John','Melissa']
>>> sex = ['Male', 'Female']
>>> name_sex = []
>>> for i in sex:
... if i == 'Male':
... name_sex.append(1)
... else:
... name_sex.append(2)
...
>>> print(name_sex)
[1, 2]
上没有>>> name_sex1 = []
>>> list1 = list(map(str, name_sex))
>>> list1
>>> for i, j in zip(name, list1):
... a1 = ' '.join([i, j])
... name_sex1.append(a1)
...
>>> for i in name_sex1:
... print(i)
...
John 1
Melissa 2
注释。加入专栏说JPA DB(不是字段!)中的哪一列引用了我们当前的实体,而targetEntity说JPA(以及那个对我来说完全过时的那个)哪个类代表我们当前的字段。