Question

嗨我试图访问我的plist里面的leg数组中的项目我希望能够获得key =＆＃34; title＆＃34;的值。来自此plist

的leg数组

我已经有了从字典中获取名为abs的值的方法，这是以下代码

let path = Bundle.main.path(forResource:"Exercise", ofType: "plist")

let dict:NSDictionary = NSDictionary(contentsOfFile: path!)!
if (dict.object(forKey: "levels") != nil) {

    if let levelDict:[String : Any] = dict.object(forKey: "levels") as? [String : Any] {

        for (key, value) in levelDict {

            if ( key == "something") {                    
                     print(value)
            }
        }
    }
}

但是我不知道如何访问leg数组来获取项目标题

Answer 1

所以我设法找到了原来问题的答案

    let path = Bundle.main.path(forResource: "Exercise", ofType: "plist")
    let dict = NSDictionary(contentsOfFile: path!)!
    let levelArray:AnyObject = dict.object(forKey: "legs")! as AnyObject

    if let nsArray:NSArray = levelArray as? NSArray{

        var levelDict:AnyObject = nsArray[1] as AnyObject //currentLevel is an Int

        //then finally I could get data from a dictionary in the array
        let Title = levelDict["title"] as AnyObject? as! String
        print(Title)

    }

所以现在这将打印leg数组中的第二项，即“leg 2”

Answer 2

在你的情况下到达具有三个元素且每个索引具有两个键对值的类型[[String:String]]的leg数组。您可以遍历该索引并获取您的值，然后迭代到其他人。

let yourLegsArray:AnyObject = dict.object(forKey: "legs")! as AnyObject

然后迭代yourLegsArray并获取Dict的内部值。

Swift 3 - 按数组索引

2 个答案: