Question

好吧，当我测试我的脚本时，它可以工作3分钟，如25分钟。有时，我发现了这个错误。

File "test.py", line 75, in free
srch = br1.open("url")
File "/usr/lib/python2.7/dist-packages/mechanize/_mechanize.py", line 203,     
in open
return self._mech_open(url, data, timeout=timeout)
File "/usr/lib/python2.7/dist-packages/mechanize/_mechanize.py", line 230, 
 in _mech_open
response = UserAgentBase.open(self, request, data)
File "/usr/lib/python2.7/dist-packages/mechanize/_opener.py", line 193, in    
open
response = urlopen(self, req, data)
 File "/usr/lib/python2.7/dist-packages/mechanize/_urllib2_fork.py", line 
344, in _open
'_open', req)
File "/usr/lib/python2.7/dist-packages/mechanize/_urllib2_fork.py", line  
332, in _call_chain
result = func(*args)
File "/usr/lib/python2.7/dist-packages/mechanize/_urllib2_fork.py", line 
1170, in https_open
return self.do_open(conn_factory, req)
 File "/usr/lib/python2.7/dist-packages/mechanize/_urllib2_fork.py", line 
 1118, in do_open
raise URLError(err)
urllib2.URLError: <urlopen error [Errno 0] Error>

要解决它，我只需重新启动脚本。我认为这个错误可能来自网络。是否有可能绕过它？或者强制我的脚本重做请求？

Answer 1

几乎取自文档...

from urllib.request import Request, urlopen
from urllib.error import  URLError

def download_url(url, attempts):
    for attempt in range(attempts):
        try:
            req = Request(url)
            response = urlopen(req)
        except URLError as e:
            if hasattr(e, 'reason'):
                print('Reason: ', e.reason)
            elif hasattr(e, 'code'):
                print('Error code: ', e.code)
        else:
            return response.read()

    return None

print(download_url('http://www.google.com', 3))

Answer 2

while 1:
    try:
        srch = br1.open("url")
        break                      
    except urllib2.URLError:
        pass

此问题已经在这里得到解答：Python urllib2 URLError HTTP status code.

绕过Urlib2.error？

2 个答案: