Question

我想从频率列表（Frtm）中逐个访问频率，并希望将它们存储在一个信号中，最后我想播放它们...... 我写了这段代码，但我不知道问题出在哪里，如果有人可以提供帮助，那么我们将不胜感激。

    function Music3 ()
      Fs = 44100;
      T = 1 / Fs;
t = 0:1 / 18:5;
      M = zeros (1, 88);
      for I = 7:88

        M (I) = round (36.8 * (2 ^ (1 / 12)) ^ (I - 6));
      endfor
      Signal = [];
      FrTm = [50, 3; 50, 3; 52, 3; 54, 3; 50, 3; 54, 3; 52, 3; 45, 3; 50, 3; 50, 3; 52, 3; 54, 3; 50, 6; 49, 3; 1, 3; 50, 3; 50, 3; 52, 3; 54, 3; 55, 3; 54, 3; 52, 3; 50, 3; 49, 3; 45, 3; 47, 3; 49, 3; 50, 6; 50, 3; 1, 3; 47, 5; 49, 1; 47, 3; 45, 3; 47, 3; 49, 3; 50, 3; 1, 3; 45, 5; 47, 1; 45, 3; 43, 3; 42, 6; 45, 3; 1, 3; 47, 5; 49, 1; 47, 3; 45, 3; 47, 3; 49, 3; 50, 3; 47, 3; 45, 3; 50, 3; 49, 3; 52, 3; 50, 6; 50, 6];
      for i = 1:length (FrTm)
        M (i) = FrTm (i);
        New = M (i);
        data = sin (2 * pi * New / Fs * t);
        Signal = [data; Signal];
      endfor
      stem(Signal);

      sound(Signal,44100);
    end

Answer 1

这是你想要的：

echo poweroff| plink ...

我将频率乘以10，否则它们太低了。

clear; clc; close all; Fs = 44100; T = 1 / Fs; sin_time_seconds = 1 t = 0:T:sin_time_seconds; Signal = []; FrTm = 10*[50, 3; 50, 3; 52, 3; 54, 3; 50, 3; 54, 3; 52, 3; 45, 3; 50, 3; 50, 3; 52, 3; 54, 3; 50, 6; 49, 3; 1, 3; 50, 3; 50, 3; 52, 3; 54, 3; 55, 3; 54, 3; 52, 3; 50, 3; 49, 3; 45, 3; 47, 3; 49, 3; 50, 6; 50, 3; 1, 3; 47, 5; 49, 1; 47, 3; 45, 3; 47, 3; 49, 3; 50, 3; 1, 3; 45, 5; 47, 1; 45, 3; 43, 3; 42, 6; 45, 3; 1, 3; 47, 5; 49, 1; 47, 3; 45, 3; 47, 3; 49, 3; 50, 3; 47, 3; 45, 3; 50, 3; 49, 3; 52, 3; 50, 6; 50, 6]; for i = 1:length (FrTm) data = sin (2 * pi .* FrTm(i) .* t); Signal = [Signal data]; end plot(Signal); sound(Signal,Fs);是您希望每个声音显示的时间。您的脚本中存在许多错误，尤其是您创建的矢量的尺寸。

在Matlab中播放音乐

1 个答案: