Question

我想知道如何从几列中验证独特的组合？

例如：

public class EmergencyContact extends AppCompatActivity {
    private static final int REQUEST_CODE = 1;

    private ArrayList<ContactPojo> contactPojolist = new ArrayList<>();
    private RecyclerView emerg_recycler;
    private RecyclerView.LayoutManager mLayoutManager;


    @Override
    protected void onCreate(Bundle savedInstanceState) {

        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_emergency_contact);
        Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
        setSupportActionBar(toolbar);
        emerg_recycler = (RecyclerView) findViewById(R.id.emerg_contact_recycler);
        mLayoutManager = new LinearLayoutManager(this);
        emerg_recycler.setLayoutManager(mLayoutManager);
        FloatingActionButton fab = (FloatingActionButton) findViewById(R.id.fab);

        Toast.makeText(this, "onCreate", Toast.LENGTH_SHORT).show();

        fab.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view) {

                Uri uri = Uri.parse("content://contacts");
                Intent intent = new Intent(Intent.ACTION_PICK, uri);
                intent.setType(ContactsContract.CommonDataKinds.Phone.CONTENT_TYPE);
                startActivityForResult(intent, REQUEST_CODE);
            }
        });
    }

    @Override
    protected void onActivityResult(int requestCode, int resultCode, Intent intent) {

        if (requestCode == REQUEST_CODE) {

            if (resultCode == RESULT_OK) {

                Uri uri = intent.getData();

                String[] projection = {ContactsContract.CommonDataKinds.Phone.NUMBER, ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME};

                Cursor cursor = getContentResolver().query(uri, projection, null, null, null);
                cursor.moveToFirst();

                int numberColumnIndex = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER);

                String number = cursor.getString(numberColumnIndex);

                int nameColumnIndex = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME);
                String name = cursor.getString(nameColumnIndex);

                ContactPojo contactPojo = new ContactPojo();
                contactPojo.setName(name);
                contactPojo.setNumber(number);
                contactPojolist.add(contactPojo);
                RentalAdapter  emergencyContact = new RentalAdapter(EmergencyContact.this, contactPojolist);
                emerg_recycler.setAdapter(emergencyContact);

            }
        }
    }
}

如果有来自伦敦的数据库John Smith，那么我想给John Smith添加记录，但不能从伦敦添加记录。

我想要从字段组合的唯一键：FirstName，LastName，Address。

请帮助。

Answer 1

对于Laravel 5.5

运行命令php artisan make:rule UniqueNameAddress。这将在app / Rules文件夹中创建一个具有给定名称（UniqueNameAddress）
在UniqueNameAddress课程中，有passes方法。这是您验证所请求的名称和地址尚未被其他用户使用的位置。您可以在passes方法中粘贴和自定义以下代码。
```
$matches = PhoneBook::whereFirstName(request(first_name))
        ->whereLastName(request(last_name))
        ->whereAddress(request(address))
        ->count();

return $matches === 0;
```
在同一个类的messages方法中，设置在出现错误时将返回的消息。

使用自定义规则，如下所示

$request->validate([
    'first_name' => ['required', new UniqueNameAddress],
]);

Laravel。请求验证。来自少数领域的独特组合

1 个答案:

对于Laravel 5.5