React Native TabNavigator this.props.navigation.state.params未定义

时间:2018-01-27 00:55:50

标签: android react-native navigator tabnavigator

我正在使用本机生成一个Android应用程序。我想通过TabNavigator传递params,但是 this.props.navigation.state.params未定义。目前我正在使用:

"react-native": "0.51.0",
"react-navigation": "^1.0.0-beta.22"

示例代码(试图仅保留相关内容):

这是我的index.js:

const RootNavigator = TabNavigator({
    Home: { screen: App },
    Design: { screen: ImageDesign }
}

这是主屏幕:

export default class App extends React.Component {

  constructor(props) {
    super(props);

    this.state = { ... }
  }

  static navigationOptions = {
    tabBarVisible: false
  };

  render() {
    const { navigate } = this.props.navigation;

    return (
      <View style={styles.container}>
        <Button title="design image"
                onPress={ () => navigate('Design',{name: 'Jane'}) }/>
      </View>
    );
  }
}

这是设计界面:

export default class ImageDesign extends React.Component {

  constructor(props) {
    super(props);

    this.state = { ... }
  }

  static navigationOptions = {
    tabBarVisible: false
  };

  render() {
    const { params } = this.props.navigation.state;

    return (
      <View>
        <Text>{ params.name }</Text>
      </View>
    );
  }
}

但不幸的是,params是未定义的,因此未定义的不是对象&#39;错误确认

我也尝试过:

<Button title="design image"
        onPress={ () => navigate('Design', {}, {type: "Navigate", routName:"ImageDesign", params: {name: 'Jane'}}) }/>

但是我不确定那样的方式

提前谢谢!

1 个答案:

答案 0 :(得分:0)

试试this.props.name。参数/道具应作为道具发送。您不应该像这样访问导航状态。